A 40.0 mL sample of 0.18 M HCI is titrated with 0.36 M CoHsNH2. Dctermine the pH at these points: At the beginning (before base
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Answer: The percent yield is, 93.4%
Explanation:
First we have to calculate the moles of Na.
Now we have to calculate the moles of
The balanced chemical reaction is,
As, 1 mole of bromine react with = 2 moles of Sodium
So, 0.189 moles of bromine react with = moles of Sodium
Thus bromine is the limiting reagent as it limits the formation of product and Na is the excess reagent.
As, 1 mole of bromine give = 2 moles of Sodium bromide
So, 0.189 moles of bromine give = moles of Sodium bromide
Now we have to calculate the percent yield of reaction
Therefore, the percent yield is, 93.4%