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sineoko [7]
3 years ago
13

Mahad and Eren made 17 ounces of pizza dough. They used 5/8 of the dough to make a pizza and used the rest to make calzones.

Mathematics
1 answer:
matrenka [14]3 years ago
6 0

9514 1404 393

Answer:

  B)  4 2/8 ounces

Step-by-step explanation:

After 5/8 of the dough was used for pizza, the remaining amount is ...

  1 -5/8 = 3/8

The difference between the amounts is then ...

  (5/8×17 oz) - (3/8×17 oz) = (5/8 -3/8)×17 oz = 2/8×17 oz = 34/8 oz

  = 4 2/8 oz

You might be interested in
2x + 3y = 3 y = 8 – 3x
pentagon [3]
2x + 3y = 3 y = 8 – 3x                     
we have 2 equations

first equations: <span>2x + 3y = 3 y
</span>the second equation: 3y = 8 – 3x => <span>8-3x=3y
</span><span>------------------------------------------------------------
2x+3y=3y</span>2x=3y-3y
2x=0
x=0

8-3x=3y
8-0=3y
8=3y
y=8/3

S={x=0 ; y=8/3 } 

8 0
3 years ago
8. What is the sum of the exterior angles of
PolarNik [594]

Answer:

D. 1080°

Step-by-step explanation:

Sum=(n-2)x180°

(8-2)x180°

6x180°

1080°

Hope it helps ❤

6 0
3 years ago
Read 2 more answers
A six-sided die is rolled two times. What is the theoretical fractional probability that the first number is even and the second
Nostrana [21]

Answer:

The theoretical probability that the first number is even and the second number is odd is \frac{1}{4}.

Step-by-step explanation:

Since each dice has six sides, and there are two die, the total amount of different outcomes are 6^2 or 36. The probability of getting an even number on the first roll is \frac{3}{6} or \frac{1}{2}, and the probability of getting an odd number on the second roll is also \frac{3}{6} or \frac{1}{2}, so the probability of getting an even number on the first roll and an odd number on the second roll is \frac{1}{2} * \frac{1}{2} = \frac{1}{4}.

6 0
3 years ago
What is the product of (3y^-4)(2y^-4)?
borishaifa [10]
(x^a)(x^b)=x^(a+b)

(ab)(cd)=(a)(b)(c)(d)

x^-m=1/(x^m)


(3y^-4)(2y^-4)=
(3)(y^-4)(2)(y^-4)=
(6)(y^-8)=
6/(y^8)
4 0
3 years ago
Read 2 more answers
Please help me with these
Alex Ar [27]
When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) \lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
\frac{\sqrt{0} - 5}{0 - 25}
= \frac{-5}{-25}
= \frac{1}{5}

<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}
= \frac{1}{5}

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
8 0
3 years ago
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