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2 years ago

What is 3y = 15x - 12 in y = mx + b form ?

Mathematics

2 answers:

Harman [31]2 years ago

6 0

The answer to the question is: y=5x-4

algol132 years ago

4 0

Nope. U need to divide it all by 3. Y mustn't have anything in front of it. So u get. Y=5x-4

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Compute: 5 ∙ (2 + 3i)

dimulka [17.4K]

Answer:

It will be equal to 40

Step-by-step explanation:

We have to compute $5\times (2+3!)$

Let first find 3 !

For this we have to use factorial concept

So 3! will be equal to 3! = 3×2×1 = 6

Now According to 6+2 = 8

And now after solving bracket we have to multiply with 5

So 5×8 = 40

So after computation $5\times (2+3!)=40$

So the final answer will be 40

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3 years ago

How can you tell that the data in the table is function or not?

stealth61 [152]

that is not a function, because there are two outputs for three. two inputs can have one output, but one input cant have two outputs.

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3 years ago

Karen paid $43.70 for a book. The price of the book was $40 what wasvthe salesvtax r

Elden [556K]

3.70 was the tax price

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2 years ago

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Rope is 5 meters long. It is cut into 8 equal parts. How long are each piece?

Murljashka [212]

Answer:

0.625m PLEASE GIVE BRAINLIEST

Step-by-step explanation:

5 ÷ 8 = 0.625

So.... each piece is 0.625m long.

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2 years ago

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25 POINTS AND BRAINLIEST PLEASE HELP ASAP

dexar [7]

M is a midpoint of BC so:

$M=\left(\dfrac{\boxed{2}\boxed{a}+a}{\boxed{2}},\dfrac{\boxed{0}+b}{2}\right)=\left(\dfrac{\boxed{3}\boxed{a}}{\boxed{2}},\dfrac{\boxed{b}}{\boxed{2}}\right)$

Length of MA:

$MA=\sqrt{\left(\dfrac{\boxed{3}a}{2}\boxed{-}\boxed{0}\right)^2+\left(\dfrac{\boxed{b}}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=
\sqrt{\left(\dfrac{\boxed{3}a}{\boxed{2}}\right)^2+\left(\dfrac{b}{2}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}$

Length of NB:

$NB=\sqrt{\left(\dfrac{a}{2}\boxed{-}\boxed{2}a\right)^2+\left(\dfrac{b}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=\sqrt{\left(\dfrac{a}{2}\boxed{-}\dfrac{\boxed{4}\boxed{a}}{2}\right)^2+\left(\dfrac{b}{2}-\boxed{0}\right)^2}=\\\\\\
\sqrt{\left(\dfrac{-3a}{2}\right)^2+\left(\dfrac{b}{\boxed{2}}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}$

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3 years ago

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