The z scores corresponding to the mean weight of a rotten apple relative to the apples from either orchard are, respectively,
![\dfrac{142-156}9\approx-1.56](https://tex.z-dn.net/?f=%5Cdfrac%7B142-156%7D9%5Capprox-1.56)
![\dfrac{165-156}{13}\approx0.69](https://tex.z-dn.net/?f=%5Cdfrac%7B165-156%7D%7B13%7D%5Capprox0.69)
The mean for the standard normal distribution is 0, which means that z scores closer to 0 represent data points that are more likely to occur. Therefore it's reasonable to believe that rotten apples occur more often in shipments from Zippy's.
Your answer:1/5 Hope this helps!
A. if two angles are complementary angles, then the sum of the measures of two angles is 90°.
It's actually 2268 square inches, or in with a little two in the corner
Given a polynomial
and a point
, we have that
![p(x_0) = 0 \iff (x-x_0) \text{\ divides\ } p(x)](https://tex.z-dn.net/?f=p%28x_0%29%20%3D%200%20%5Ciff%20%28x-x_0%29%20%5Ctext%7B%5C%20divides%5C%20%7D%20p%28x%29)
We know that our cubic function is zero at -4, 0 and 5, which means that our polynomial is a multiple of
![(x+4)(x)(x-5) = x(x+4)(x-5)](https://tex.z-dn.net/?f=%28x%2B4%29%28x%29%28x-5%29%20%3D%20x%28x%2B4%29%28x-5%29)
Since this is already a cubic polynomial (it's the product of 3 polynomials with degree one), we can only adjust a multiplicative factor: our function must be
![f(x) = ax(x+4)(x-5),\quad a \in \mathbb{R}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20ax%28x%2B4%29%28x-5%29%2C%5Cquad%20a%20%5Cin%20%5Cmathbb%7BR%7D)
To fix the correct value for a, we impose
:
![f(4) = 4a(4+4)(4-5) = -32a = 96](https://tex.z-dn.net/?f=f%284%29%20%3D%204a%284%2B4%29%284-5%29%20%3D%20-32a%20%3D%2096)
And so we must impose
![-32a=96 \iff a = -\dfrac{96}{32} = -3](https://tex.z-dn.net/?f=-32a%3D96%20%5Ciff%20a%20%3D%20-%5Cdfrac%7B96%7D%7B32%7D%20%3D%20-3)
So, the function we're looking for is
![f(x) = -3x(x+4)(x-5)=-3x^3+3x^2+60x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20-3x%28x%2B4%29%28x-5%29%3D-3x%5E3%2B3x%5E2%2B60x)