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3 years ago

What is the solution set for this inequalty? -8x + 40> -16

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

3 0

Answer:

x < 7

Step-by-step explanation:

-8x + 40> -16

Subtract 40 from each side

-8x + 40-40> -16-40

-8x >-56

Divide each side by -8, remembering to flip the inequality

-8x/-8 < -56/-8

x < 7

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What is the soloution to -4x+2=-14

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Answer:

x = 4

Step-by-step explanation:

subtract 2 from both sides. then -4x is equal to -16. divide by -4 which gives you 4. Hope this helped!

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The scores on a test are normally distributed with a mean of 110 and a standard deviation of 22. What is the score that is 3 sta

Alborosie

Answer:

Step-by-step explanation:

If the mean is 110, and the standard devaition is 22,

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4 years ago

Please help me with this.A rectangular field is

Karolina [17]

First, let's get the perimeter of the rectangle:
$P=2W+2L$
$P=130m+210m$
$P=340m$
Then, let's get the area of the bigger one:
$A=WL$
$A=65m*105m$
$A=6825m^2$

Then let's try using a rectangle with a smaller ratio:
$P=100m+240m$
$P=340m$
Then:
$A=50m*120m$
$A=6000m^2$

If you used a square:
$P=170+170$
$P=340$
$A=WL$
$A=85^2$
$A=7225$

There you have it. A rectangle with a smaller area with the same perimeter.
What does it show? The smaller the difference you get from width and length, the larger the area is.

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3 years ago

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A rectangular parking lot has a length that is 5 yards greater than the width the area of the parking lot is 300 yd.² find the l

ArbitrLikvidat [17]

Answer:

width=5yd and length=10yd

Step-by-step explanation:

To solve this problem, you need to start by asking what you do and don't know (always where to start with word problems)

We know that Area (A) = Length (L) * Width (W)

You know Area (A) = 50 sq. yds.

You don't know anything about the width, so let's just say Width (W) = x

And you know that the length is 5 yds longer than the width, so L = W + 5yd and, since W = x, we can say L = x + 5yd

Now, we recall that A = L * W, and, since A = 50, we can say 50 sq yd = L * W.

Well, now just plug in. What does W equal and L equal?

From above we plug in and can say that 50 sq yd = x * (x + 5 yd).

Multiply it out and you get 50 = x^2 + 5x (removing units for a moment so they don't clutter the lines).

Now there are a number of ways to solve this. You can tell (because of the "x^2") that it is quadratic. So let's get it equal to zero:

0 = x^2 + 5x - 50

Now you can factor it, use your quadratic formula, or (if you hated yourself) do it as a completing the square problem. I'm going to factor.

I can see from going through a list in my head that the factors 10 and -5 multiply to -50 and add to 5, so I know that

0 = x^2 + 5x - 50 = (x + 10)(x - 5)

And so you know that x = -10 or 5.

Well, you know the parking lot cannot be -10 yd long. So we must say that W = x = 5, and, since L = W + 5, then L = 5+5 = 10. So your width is 5 yd and length is 10 yd.

<h2>mark me brainlist</h2>

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