Answer:
The only problem was that now it costs more so not really
Step-by-step explanation:
I think its an opinion question
The system of the equation doesn't give the solution at (-3, -6).
<h2>Given to us</h2>
<h3>Equation 1,</h3>
-4x+y = 6
solve for y

<h3>Equation 2,</h3>
5x-y =21
substitute the value of y in equation 2,

Substitute the value of x in equation 2,

We can see that the solution of the two equations is at (27, 114). Also, it can be verified by plotting the line on the graph.
Hence, the system of the equation doesn't give the solution at (-3, -6).
Learn more about system of equations:
brainly.com/question/12895249
Answer:
D. clockwise 90 degrees , rotation , enlargement
Hi,
Roots are 2, -1,-3.So y=(x-3)(x+1)(x+3)
Answer B
The formula is f(x) = a x ^ 3 + b x ^ 2 + c x + d
f '(x) = 3ax^2 + 2bx + c.
f(- 3) = 3 ==> - 27a + 9b - 3c + d = 3
f '(- 3) = 0 (being a most extreme) ==> 27a - 6b + c = 0.
f(1) = 0 ==> a + b + c + d = 0
f '(1) = 0 (being a base) ==> 3a + 2b + c = 0.
-
Along these lines, we have the four conditions
- 27a + 9b - 3c + d = 3
a + b + c + d = 0
27a - 6b + c = 0
3a + 2b + c = 0
Subtracting the last two conditions yields 24a - 8b = 0 ==> b = 3a.
Along these lines, the last condition yields 3a + 6a + c = 0 ==> c = - 9a.
Consequently, we have from the initial two conditions:
- 27a + 9(3a) - 3(- 9a) + d = 3 ==> 27a + d = 3
a + 3a - 9a + d = 0 ==> d = 5a.
Along these lines, a = 3/32 and d = 15/32.
==> b = 9/32 and c = - 27/32.
That is, f(x) = (1/32)(3x^3 + 9x^2 - 27x + 15).