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3 years ago

Which Is NOt A function

Mathematics

1 answer:

Dominik [7]3 years ago

3 0

Answer:

Bottom right.

Step-by-step explanation:

An input cannot have two outputs.

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3[–x + (2 x + 1)] = x – 1

photoshop1234 [79]

Answer:

Step-by-step explanation:

$3[-x + (2 x + 1)] = x -1\\\\\mathrm{Expand\:}3\left(-x+\left(2x+1\right)\right):\quad 3x+3\\3x+3=x-1\\$

Collect like terms

$3x -x =-1-3$

Add similar elements

$2x = -4\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\frac{2x}{2}=\frac{-4}{2}\\\\Simplify\\\\x = -2$

3 0

3 years ago

Write an equation for each condition listed.

Svetlanka [38]

Look for the y-intercept
since we know the slope is 3 we just going to plug in
-5=3(1)+y
-5-3=y
so the y-intercept is 8 now you can find the equation
y=3x-8

6 0

3 years ago

Evaluate. 5x + 2y2-y3; x =2 and y=4

Elanso [62]

5x+2y2-y3:x=2 and y=4

5(2)+2(4)2-(4)3

10+8(2) -12

10+16-12

26-12

=14

7 0

3 years ago

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

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$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$