The graph that would allow the comparison between the median number of teeth for mammals and reptiles easily is a Box Plot.
<h3>Median</h3>
The median of a set of data is the midpoint of values in a data set. It shows the value that divides the data set into two halves.
<h3>Box plot</h3>
- A box plot is a type of graph used in data analysis to visualize the distribution of numerical data and skewness by displaying the data quartiles and averages.
Box plots are also known as box and whisker plot.
- Box plots are used to compare visually differences among different samples or groups such medians, ranges, and outliers.
Therefore, the graph that would allow the comparison between the median number of teeth for mammals and reptiles easily is a Box Plot.
Learn more about Box plots and median at: brainly.com/question/16796572
Answer:
2/5
Step-by-step explanation:
Ok there are 4+3+1+2 pairs of socks in all... Aka 10 sock pairs in all.
There are 4 white pairs. So the probability she selects a white pair is 4/10.
4/10 can be reduced to 2/5.
Well, assuming that you need to round to the nearest whole number, what is six closer to? 0, or 10? The answer is 10. Therefore, you would round up to 33. Hope this helps!
Answer:
none of them
Step-by-step explanation:
Two lines are perpendicular when satisfy the next equation: m1*m2 = -1, where m1 and m2 are the slopes o the lines.
line 1:
y – 1 = (x+2)
y = x + 3
slope of line 1 = 1
line 2:
y + 2 = –3(x – 4)
y + 2 =
-3*x + 12
y = -3*x + 10
slope of line 2 = -3
m1*m2 = 1*(-3
) = -3
They are not perpendicular
line 3:
y − 5 = 3(x + 11)
y − 5 = 3*x + 33
y = 3*x + 38
slope of line 3 = 3
m1*m3 = 1*3 = 3
They are not perpendicular
line 4:
y = -3x –
slope of line 4 = -3
m1*m4 = 1*(-3
) = -3
They are not perpendicular
line 5:
y = x – 2
slope of line 5 = 1
m1*m5 = 1*1 = 1
They are not perpendicular
line 6:
3x + y = 7
y = -3x + 7
slope of line 6 = -3
m1*m6 = 1*(-3
) = -3
They are not perpendicular

The false (wrong) equation among them is : A

Because any number in a modulus comes out to be positive.