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alisha [4.7K]
3 years ago
14

Given that f(x) = 5x+3 and g(x) = x²-3.Finda f(4)b) f(g(x))C). g( f (2))​

Mathematics
1 answer:
frosja888 [35]3 years ago
6 0

Answer:

given;

f(x) = 5x+3

g(x) = x²-3.

Step-by-step explanation:

a f(4)=5×4+3=23

b) f(g(x))=f(x²-3)=5{x²-3)+3=5x²-15+3=5x²-12

C). g( f (2))=g(5×2+3)=13²-3=166

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Answer:

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                                             4                                                         3        

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-Lexi

6 0
3 years ago
Add the polynomials <br><br><br> (-12x^5-7x^3+12x^2+11)+(4x^3+6x^2-6x+3)
tatuchka [14]

Answer:

-12x^5-3x^3+18x^2+14

6 0
3 years ago
Please help.
Mashcka [7]
V=(1/3)(area of the base)(<span>altitude)

V=</span><span>(1/3)(</span>6²)(6)= 72 m³
5 0
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Harrizon [31]

Answer:

x(2x-17)

Step-by-step explanation:

2x^2 -11x-6x

2x^2-17x

x is common

x(2x-17)


6 0
3 years ago
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Draw a line representing the "rise" and a line representing the "run" of the line, State
Alexxx [7]

Answer:

The slope of the line m = 1

The equation of the straight line x -y -7=0

Step-by-step explanation:

<u><em>Explanation:-</em></u>

In the given graph

The points are ( 7,0) and ( 0, -7)

The slope of the line

            m = \frac{y_{2}- y_{1}  }{x_{2}-x_{1}  } = \frac{-7-0}{0-7} = \frac{-7}{-7} = 1

The equation of the straight line passing through the point (7,0) and slope m=1

    y - y₁ = m (x - x₁)

    y - 0 = 1( x-7)

   y = x -7

   x - y -7=0

<u><em>Final answer:-</em></u>

The slope of the line m = 1

The equation of the straight line x -y -7=0

<u><em></em></u>

4 0
3 years ago
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