2 years ago

Given that f(x) = 5x+3 and g(x) = x²-3.Finda f(4)b) f(g(x))C). g( f (2))

Mathematics

1 answer:

frosja888 [35]2 years ago

6 0

Answer:

given;

f(x) = 5x+3

g(x) = x²-3.

Step-by-step explanation:

a f(4)=5×4+3=23

b) f(g(x))=f(x²-3)=5{x²-3)+3=5x²-15+3=5x²-12

C). g( f (2))=g(5×2+3)=13²-3=166

You might be interested in

A zoo has six adult tigers. Their caretaker orders a total of 40.8 kilograms of meat for them each day. Each tiger receives the

lbvjy [14]

Each tiger gets 6.8 kilograms of meat a day. I used a calculator to divide 60.8 by 6.

8 0

3 years ago

X+3y=5 -2x-6y=-10 Solve using elimination

RSB [31]

Slimination
multiply first equaiton by 2
2x+6y=10
add to second equiaotn
2x-2x+6y-6y=10-10
0=0
this is true so therfor they are the same equaiton

so solve
x+3y=5
3y=-x+5
y=-1/3x+5/3

subsituter values for x and get valuse for y

if x=2 then y=1

3 0

3 years ago

the combination for a lock is a 3 didget number the didgets are the prime factors of 42 listing from least to greatest what is t

zhannawk [14.2K]

42 = 2 * 3 * 7

So, the combination for the lock is 237

3 0

3 years ago

4 1/6 pounds of rice is divided into 5 equal portions. What is the weight in pounds of each portion?

Katen [24]

5/6 or 0.83 lbs is the anwser

4 0

2 years ago

14.7 divided by 2.2=

GenaCL600 [577]

Answer:

6.68181818182

Step-by-step explanation:

3 0

3 years ago

Given that f(x) = 5x+3 and g(x) = x²-3.Finda f(4)b) f(g(x))C). g( f (2))​

Given that f(x) = 5x+3 and g(x) = x²-3.Finda f(4)b) f(g(x))C). g( f (2))