I need to know what this is

Mathematics

1 answer:

ycow [4]2 years ago

6 0

Answer:

$★\:\: \frac{3 {x}^{3} - 18 {x}^{2} + 27x}{2 {x}^{2} + 2x - 12}\:when\:x≠2,\:3 \\ = \frac{3x( {x}^{2} - 6x + 9) }{2( {x}^{2} + x - 6) } \\ = \frac{3x( {(x)}^{2} - 2 \times (3) \times (x) + {(3)}^{2} ) }{2( {x}^{2} + 3x - 2x - 6) } \\ = \frac{3x {(x - 3)}(x - 3) }{2(x(x + 3) - 2(x + 3))} \\ = \boxed{‡ \frac{3x {(x - 3)}^{2} }{2(x + 3)(x - 2)}‡}✓$

<h3><u>3x(x-3)²/2(x+3)(x-2)</u> is the right answer.</h3>

You might be interested in

F(x)= -x over x^2+5 on the domain [0,4]

BartSMP [9]

If you're asking for extrema, like the previous posting

well

$\bf f(x)=\cfrac{-x}{x^2+5}
\\\\\\
\cfrac{df}{dx}=\cfrac{(x^2+5)+2x^2}{(x^2+5)^2}\implies \cfrac{df}{dx}=\cfrac{5+3x^2}{(x^2+5)^2}\impliedby 
\begin{array}{llll}
using\ the\\
quotient\ rule
\end{array}$

like the previous posting, since this rational is identical, just that the denominator is negative, the denominator yields no critical points

and the numerator, yields no critical points either, so the only check you can do is for the endpoints, of 0 and 4

f(0) = 0 <---- only maximum, and thus absolute maximum

f(4) ≈ - 0.19 <---- only minimum, and thus absolute minimum

5 0

3 years ago

PLEASE HELP ME!!!!!!!!

iren [92.7K]

SAS

there is an included angle on each triangle so if you look carefully there are two sides in which are given

5 0

2 years ago

Simplify this expression <br> 2/3 (6c+9)−(8c−5)

Ludmilka [50]

Answer:

This is the right answer −4c+11