i believe it is 645, 500 !
First, you multiply $55.96 by $0.12 and you get $6.7152. Then, multiply $49.96 by $0.14 and you get $6.9944. If you subtract $69944-$6.7152 you get your answer which is $0.2792.
It sounds like initially we have a total of 18*5 = 90. Then we are adding 5 + 4 +3 +2 +1 to this.
so that gives us 105.
105/5 = 21
Answer:
The probability that the wait time is greater than 14 minutes is 0.4786.
Step-by-step explanation:
The random variable <em>X</em> is defined as the waiting time to be seated at a restaurant during the evening.
The average waiting time is, <em>β</em> = 19 minutes.
The random variable <em>X</em> follows an Exponential distribution with parameter
.
The probability distribution function of <em>X</em> is:

Compute the value of the event (<em>X</em> > 14) as follows:

Thus, the probability that the wait time is greater than 14 minutes is 0.4786.
2.96 meters per second is the answer I'm getting. I took the total seconds and divided it by how many times he ran around the track to get his speed for lap and then I divided his lap speed by how long the track was to get his meters per second