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il63 [147K]
3 years ago
7

Using the graph, determine the coordinates of the roots of the parabola​

Mathematics
1 answer:
Hatshy [7]3 years ago
6 0

Answer:

(-8, 0) and (-2, 0)

Step-by-step explanation:

The root of a parabola are the places at which the parabola intersects the x-axis. As one can see, on the graph these points are the following: (-8, 0) and (-2, 0). Thus, the roots of the parabola are (-8, 0) and (-2, 0).

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Write the expression as a square of a binomial: 49x^2+12xy+64y^2
DiKsa [7]
STEP
1
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Equation at the end of step 1

((49 • (x2)) + 12xy) + 26y2
STEP
2
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Equation at the end of step
2
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(72x2 + 12xy) + 26y2
STEP
3
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Trying to factor a multi variable polynomial

3.1 Factoring 49x2 + 12xy + 64y2

Try to factor this multi-variable trinomial using trial and error

Factorization fails

Final result :
49x2 + 12xy + 64y2
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What value of x makes the equation 5(4x - 1)=4(2.5x+8) true?
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What is StartFraction negative 23 over 6 EndFraction minus StartFraction 7 over 3 EndFraction
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Step-by-step explanation:

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What are the side lengths of the rectangle area 40 perimeter 26
shusha [124]
Recall the formula for finding the area of a rectangle:

           Area = Length × Width

Recall the formula for finding the perimeter of a rectangle:

         Perimeter = 2 ( Length + Width )

Given in your problem:
        Area = 40 sq. units
        Perimeter = 26 units

Required to solve for:
        Length (L) and width (W)

• First, substitute the given to the formula:

        Area = Length x Width
          40 = L × W      ⇒   equation number 1

       Perimeter = 2 ( Length + Width )
            26 = 2 ( L + W )     ⇒   equation number 2


• Simplifying equation number 2,
           13 = L + W

 • Rearranging the equation, 

         L = 13 - W   ⇒   equation 3

Substituting equation 3 from equation 1:

      ( equation 1 )               40 = (L)(W)
      ( equation 3 )                L = 13 - W
                                      40 = (13 - W) (W)
                                      40 = 13W - W² 
      ( regrouping )          W² - 13W + 40 = 0
      ( factoring )             (W - 8) (W - 5) = 0
                                     W - 8 = 0    ;     W - 5 = 0
                                        W = 8      ;        W = 5
   
Therefore, there are 2 possible values for the width of the rectangle. It can be 8 units or 5 units.

• Now to solve for the length of the rectangle, substitute the two values of width to equation 3.

      (equation 3)        L = 13 - W
                       for W = 8    ⇒   L = 13 - 8
                                                   L = 5 units
                   
                       for W = 5    ⇒  L = 13 - 5
                                                   L = 8 units

3 0
2 years ago
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