84+63i would be the complex conjugate of84-63i
Answer:
The numbers slowly decrease by 4 so we can determine that the 40th sequence is -70.
Step-by-step explanation:
12 times 3 is equal to 36 so 36 is your answer
Pair up the terms into separate groups. Then factor each group individually (pull out the GCF). Once that is finished, you factor out the overall GCF to complete the full factorization.
8r^3 - 64r^2 + r - 8
(8r^3 - 64r^2) + (r - 8)
8r^2(r - 8) + (r - 8)
8r^2(r - 8) + 1(r - 8)
(8r^2 + 1)(r - 8)
So the final answer is (8r^2 + 1)(r - 8)
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Edit:
Problem 1b) Follow the same basic steps as in part A
28v^3 + 16v^2 - 21v - 12
(28v^3 + 16v^2) + (-21v - 12)
4v^2(7v + 4) + (-21v - 12)
4v^2(7v + 4) - 3(7v + 4)
(4v^2 - 3)(7v + 4)
The answer to part B is (4v^2 - 3)(7v + 4)
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Second Edit:
I apologize for the first edit. I misread what you were asking initially. Here is problem 2A. We follow the same basic steps as in 1a) and 1b). You'll need to rearrange terms first
27mz - 12nc + 9mc - 36nz
27mz + 9mc - 12nc - 36nz
(27mz + 9mc) + (-12nc - 36nz)
9m(3z + c) + (-12nc - 36nz)
9m(3z + c) -12n(c + 3z)
9m(3z + c) -12n(3z + c)
(9m - 12n)(3z + c)
3(3m - 4n)(3z + c)
Answer: fg(x) = 16x² + 32x
Method:
First you must substitute g(x) into f(x).
Where the x is in the equation f(x) substitute the equation of g(x).
So it should be fg(x) = (x4)²+ 8(x4).
Then simplify the equation to
fg(x) = 16x² + 32x
