<u>Answer</u><u>:</u>
<h2>
C. 9/12</h2>
<u>Explanation:</u>
<em>6</em><em>/</em><em>8</em><em> </em><em>simplifies </em><em>to </em><em>3</em><em>/</em><em>4</em>
<em>3</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>=</em><em> </em><em>9</em>
<em>4</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>=</em><em> </em><em>1</em><em>2</em>
<em>Since </em><em>they </em><em>are </em><em>both </em><em>multiples </em><em>of </em><em>3</em><em>,</em><em> </em><em>it's </em><em>e</em><em>quivalent</em><em> </em><em>to </em><em>6</em><em>/</em><em>8</em><em>.</em>
Answer:
a: no the sample size is too small
b: Yes, the distribution is normal with a mean of 40 and standard deviation of 12
Step-by-step explanation:
a: If n < 30, we need to know that the sample is normally distributed or else we can't determine anything. When sample sized get very large, they usually resemble normally distributed data sets so we can still make conjectures even if the data isn't officially normally distributed
b: The question tells us that the sample is normally distributed, so even though n < 30, we can still make conjectures about the population
It is the last one.
A pre-image is the original before another shape is created from it, either dilated, translated, reflected, or rotated.
Answer:
see below
Step-by-step explanation:
<h3>Given</h3>
- Distance is 142.2 m, correct to 1 decimal place
- Time is 7 seconds, correct to nearest second
<h3>To find:</h3>
- Upper bound for the speed
<h3>Solution </h3>
<em>Upper bound for the speed = upper bound for distance/lower bound for time</em>
- Upper bound for distance = 142.25 m (added 0.1/5 = 0.05)
- Lower bound for time = 6.5 seconds (subtracted 1/2 = 0.5)
<u>Then, the speed is:</u>
- 142.25/6.5 = 21.88 m/s
- 21.88 = 21.9 m/s correct to 1 decimal place
- 21.88 = 22 m/s correct to nearest m/s
The answer to this is question is C
