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4 years ago

The 7th grade has 220 tudents. There are 3/5 girls. How many boys are there in 7th grade

Mathematics

1 answer:

Helga [31]4 years ago

3 0

Answer:

Step-by-step explanation:

Let's see - if there are 3/5 girls, there must be 2/5 boys. Assuming everyone in the class is binary, of course.

So 2/5 of 220 is the number of boys. When you see "of," always think multiplication!

2/5 of 220

2/5 * 220 = 88 boys in 7th grade

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Michael is 5 years old than rui feng and. Vishal is thrice as old as micheal if rui feng is 3 years old find Michael present age

lorasvet [3.4K]

Answer:

a) Micheal's present age = 8 years old

b) The sum of their ages in 6 years time = 63 years.

Step-by-step explanation:

From the above question, we know that

Rui feng is 3 years old

We are told that

• Michael is 5 years old than Rui feng

Micheal's present age is calculated as:

= 5 + Rui feng's age

= 5 + 3 = 8 years

• Vishal is thrice as old as Micheal

Vishal's present age is calculated as

= 3(Micheal age)

= 3(8)

= 24 years.

The sum of their ages in six years time

= ( 3 + 6) +( 8 + 6) + ( 24 + 6)

= 18 + 15 + 30

= 63 years

Therefore, a) Micheal's present age = 8 years old

b) The sum of their ages in 6 years time = 63 years.

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Answer:

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Step-by-step explanation:

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Marine ecologists estimate the reproduction curve for swordfish in a fishing ground to be f(p) = −0.01p2 + 9p, where p and f(p)

Nimfa-mama [501]

Answer:

The population that gives the maximum sustainable yield is 45000 swordfishes.

The maximum sustainable yield is 202500 swordfishes.

Step-by-step explanation:

Let be $f(p) = -0.01\cdot p^{2}+9\cdot p$ , the maximum sustainable yield can be found by using first and second derivatives of the given function: (First and Second Derivative Tests)

First Derivative Test

$f'(p) = -0.02\cdot p +9$

Let equalize the resulting expression to zero and solve afterwards:

$-0.02\cdot p + 9 = 0$

$p = 450$

Second Derivative Test

$f''(p) = -0.02$

This means that result on previous part leads to an absolute maximum.

The population that gives the maximum sustainable yield is 45000 swordfishes.

The maximum sustainable yield is:

$f(450) = -0.01\cdot (450)^{2}+9\cdot (450)$

$f(450) =2025$

The maximum sustainable yield is 202500 swordfishes.

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3 years ago