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OLga [1]
4 years ago
14

Consider the functions f(x) = (4/5)^x and g(x) = (4/5)^x  + 6. What are the ranges of the two functions?

Mathematics
2 answers:
Marianna [84]4 years ago
6 0

THE RANGES OF THE TWO FUNCTIONS ARE
Y>0
Y>6

Alborosie4 years ago
4 0

The <u>range</u> of the <u>function</u> is the <u>set</u> of all possible <u>values</u> that function can take. Both given functions

y=\left(\dfrac{4}{5}\right)^x and y=\left(\dfrac{4}{5}\right)^x+6

are <u>exponential functions</u> with base \dfrac{4}{5}.

The graphs of these function you can see in attached diagram.

The range of the function y=\left(\dfrac{4}{5}\right)^x is (0,\infty).

The range of the function y=\left(\dfrac{4}{5}\right)^x+6 (this function is translated function  y=\left(\dfrac{4}{5}\right)^x 6 units up) is (6,\infty).


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Can someone help me find the distance between the points (-5,3) and (-4,2)
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Answer: 1.4142

Step-by-step explanation:

Input Data :Point 1 (xA,yA) = (-5, 3) Point 2(xb,yB) = (-4, 2)

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Formula :Distance between two points = √(xB-xA)^2+(yB−yA)^2

Solution :

Distance between two points =  √(−4−−5)2+(2−3)2= √12+(−1)2= √1+1= √2 = 1.4142

Distance between points (-5, 3) and (-4, 2) is 1.4142

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