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OLga [1]
3 years ago
14

Consider the functions f(x) = (4/5)^x and g(x) = (4/5)^x  + 6. What are the ranges of the two functions?

Mathematics
2 answers:
Marianna [84]3 years ago
6 0

THE RANGES OF THE TWO FUNCTIONS ARE
Y>0
Y>6

Alborosie3 years ago
4 0

The <u>range</u> of the <u>function</u> is the <u>set</u> of all possible <u>values</u> that function can take. Both given functions

y=\left(\dfrac{4}{5}\right)^x and y=\left(\dfrac{4}{5}\right)^x+6

are <u>exponential functions</u> with base \dfrac{4}{5}.

The graphs of these function you can see in attached diagram.

The range of the function y=\left(\dfrac{4}{5}\right)^x is (0,\infty).

The range of the function y=\left(\dfrac{4}{5}\right)^x+6 (this function is translated function  y=\left(\dfrac{4}{5}\right)^x 6 units up) is (6,\infty).


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Answer:

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the equation will be:

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Step-by-step explanation:

Given the equation

y+2\:=-3\left(x\:-\:4\right)

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so substituting the value y = -2 in the equation to find the missing value

\left(-2\right)+2\:=-3\left(x\:-\:4\right)

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\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

-3\left(x-4\right)=-2+2

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Therefore, the missing value in the solution to

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