Answer:
Number of year to get $10,000 as interest = 7.5 year (Approx)
Step-by-step explanation:
Given:
Initial investment = $20,000
Interest on investment = $10,000
Rate of interest = 5.6% = 0.056
Find:
Number of year to get $10,000 as interest:
Computation:
![Interest\ on\ investment = Initial\ investment[(1+r)^n-1]\\\\10,000 = 20,000[(1+0.056)-1]\\\\0.5=(1.056)^n-1\\\\1.5 =(1.056)^n\\\\n=7.44](https://tex.z-dn.net/?f=Interest%5C%20on%5C%20investment%20%3D%20Initial%5C%20investment%5B%281%2Br%29%5En-1%5D%5C%5C%5C%5C10%2C000%20%3D%2020%2C000%5B%281%2B0.056%29-1%5D%5C%5C%5C%5C0.5%3D%281.056%29%5En-1%5C%5C%5C%5C1.5%20%3D%281.056%29%5En%5C%5C%5C%5Cn%3D7.44)
Number of year to get $10,000 as interest = 7.44
Number of year to get $10,000 as interest = 7.5 year (Approx)
Answer:
distance bw 2,5 is 2 digits
and -4,7 is 11 digits
Step-by-step explanation:
The restrictions are:
1) x ≥ 0
2) number of lower bowl seats = 65% * 18500 = 12,025
=> x ≤ 12,025
3) y ≥ 0
4) number of upper bowl seats = 35% * 18500 = 6,475
=> y ≤ 6,475
It is not necessary to state that x + y ≤ 18,500 because it is included in the other restrictions.
Answer:
Step-by-step explanation:
100 +30+2+.60 or .6
