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vodomira [7]
3 years ago
15

Suppose that the function LaTeX: f(x) f ( x ) is shifted horizontally to the right by LaTeX: a a , reflected across the LaTeX: x

x -axis, and shifted vertically down by LaTeX: b b to become the function LaTeX: g(x) g ( x ) . Write the function LaTeX: g(x) g ( x ) in terms of LaTeX: f(x) f ( x ) and explain each of the shifts
Mathematics
1 answer:
Sveta_85 [38]3 years ago
3 0

Answer:

g(x) = (x-a,-y - b)

Step-by-step explanation:

Given

Represent f(x) as follows:

f(x) = (x,y)

Transformations:

Horizontally shifted right by a

Reflected across x axis

Vertically shifted down by b

Taking the transformations one after the other.

Horizontally shifted right by a

When a function is shifted right, the resulting function is:

f' = (x-a,y)

Reflected across x axis

Here, the x axis remains unaltered while the y axis is negated

f' = (x-a,y)

becomes

f" = (x-a,-y)

Vertically shifted down by b

When a function is shifted down by b, the resulting function is:

f"' = f" - b

i.e, subtract b from the function (f(x) or y, as the case may be)

So, we have:

f"'  = (x-a,-y - b)

Represent f"' with g(x)

g(x) = (x-a,-y - b)

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There are two ways to work this out: normal variables or using "imaginary" numbers.

Normal variables:
(7+2i)(3-i)\\(7*3)+[7*(-i)]+(3*2i)+[2i*(-i)]\\21-7i+6i-2i^{2}\\\\21-i-2i^{2}

Imaginary numbers:
Using the result from earlier:
21-i-2i^{2}
Now since i = \sqrt{-1}, then the expression becomes:
21-i-2i^{2}\\21-i-2(\sqrt{-1})^{2}\\21-i+(-2)(-1)\\21-i+2\\\\23-i
7 0
3 years ago
Six times a number is 45 greater than the product of the number and -3. Find the number.
LiRa [457]

Answer:

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Step-by-step explanation:

6a = (a*-3) + 45

then:

6a = -3a + 45

6a + 3a = 45

9a = 45

a = 45/9

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Check:

6*5 = (5*-3) + 45

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8 0
3 years ago
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Fiesta28 [93]

Answer:

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Answer:

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Step-by-step explanation:

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