Answer:
Odd integers
Step-by-step explanation:
The range is odd integers, if you add 1 to any even integer it becomes an odd integer. 2+1=3; 10+1=11
Answer:
Option A
Option C
Step-by-step explanation:
A relationship is defined as a function if and only if each element of the "domain" set is assigned only one element of the "range" set. That is, there is only one output value y assigned to each input value x.
The relation x = 3 is not a function because there are infinite output values y, assigned to the same input element x.
(3, 2), (3, 5) (3, 9) (3,10000)
<u><em>Then the option A is true</em></u>
<em><u>Option C is also true,</u></em> the equation of the line shown is
![x = 3](https://tex.z-dn.net/?f=x%20%3D%203)
The rest of the options are false because x = 3 is not a function
36x² - 100 = 4(9x²-25) = 4(3x+5)(3x-5)
B. 4(3x+5)(3x-5)
ANSWER: ∠T = 32.4°
Remember the formula for the basic trig functions: SOH CAH TOA
Since you want to find cosine for <T, you need the adjacent side length as well as the hypotenuse's length which can be found using the Pythagoras's Theorem
with <em>a </em> and <em>b</em> being the side lengths and <em>c</em> being the hypotenuse.
Using the theorem, we get c=37
Now use the cosine formula to get <T = 12/37 to get the final answer.
Answer:
![P(A \cap B)](https://tex.z-dn.net/?f=%20P%28A%20%5Ccap%20B%29)
And we can use the following formula:
![P(A \cap B)= P(A)* P(B)](https://tex.z-dn.net/?f=%20P%28A%20%5Ccap%20B%29%3D%20P%28A%29%2A%20P%28B%29)
And replacing the info we got:
![P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476](https://tex.z-dn.net/?f=%20P%28A%20%5Ccap%20B%29%20%3D%20%5Cfrac%7B5%7D%7B7%7D%20%5Cfrac%7B2%7D%7B3%7D%3D%20%5Cfrac%7B10%7D%7B21%7D%3D0.476)
Step-by-step explanation:
We define two events for this case A and B. And we know the probability for each individual event given by the problem:
![p(A) = \frac{5}{7}](https://tex.z-dn.net/?f=%20p%28A%29%20%3D%20%5Cfrac%7B5%7D%7B7%7D)
![p(B) = \frac{2}{3}](https://tex.z-dn.net/?f=%20p%28B%29%20%3D%20%5Cfrac%7B2%7D%7B3%7D)
And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:
![P(A|B) = P(A)](https://tex.z-dn.net/?f=%20P%28A%7CB%29%20%3D%20P%28A%29)
![P(B|A) = P(B)](https://tex.z-dn.net/?f=%20P%28B%7CA%29%20%3D%20P%28B%29)
And for this special case we want to find this probability:
![P(A \cap B)](https://tex.z-dn.net/?f=%20P%28A%20%5Ccap%20B%29)
And we can use the following formula:
![P(A \cap B)= P(A)* P(B)](https://tex.z-dn.net/?f=%20P%28A%20%5Ccap%20B%29%3D%20P%28A%29%2A%20P%28B%29)
And replacing the info we got:
![P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476](https://tex.z-dn.net/?f=%20P%28A%20%5Ccap%20B%29%20%3D%20%5Cfrac%7B5%7D%7B7%7D%20%5Cfrac%7B2%7D%7B3%7D%3D%20%5Cfrac%7B10%7D%7B21%7D%3D0.476)