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adell [148]
3 years ago
14

a square dance set requires 4 couples 8 dancers with each couple standing on one side of a square. There are 250 people at a squ

are dance. What is the greatest number of sets possible at the dance?
Mathematics
1 answer:
sveta [45]3 years ago
7 0

Given:

1 set requires 4 couples 8 dancers.

Total number of people at a square dance = 250.

To find:

The greatest number of sets possible at the dance.

Solution:

We have,

Total people = 250

1 set = 8 people.

\text{Number of possible sets}=\dfrac{\text{Total people}}{\text{People required for 1 set}}

\text{Number of possible sets}=\dfrac{250}{8}

\text{Number of possible sets}=31.25

Number of possible sets cannot be a decimal or fraction value. So, approx. the value to the preceding integer.

\text{Number of possible sets}\approx 31

Therefore, the number of possible sets at the dance is 31.

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Alexandra [31]

Answer:

X \sim Binom(n=157, p=0.52)

The probability mass function for the Binomial distribution is given as:

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nCx=\frac{n!}{(n-x)! x!}

And we want this probability:

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And we can use the following Excel code to find the exact answer:

"=BINOM.DIST(75,157,0.52,TRUE)"

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The other way to solve the problem is using the normal approximation

We need to check the conditions in order to use the normal approximation.

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So we see that we satisfy the conditions and then we can apply the approximation.

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We want this probability:

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And using the continuity correction we have this:

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We can use the z score given by this formula Z=\frac{x-\mu}{\sigma}.

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Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=157, p=0.52)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want this probability:

P(X

And we can use the following Excel code to find the exact answer:

"=BINOM.DIST(75,157,0.52,TRUE)"

And we got 0.1633

The other way to solve the problem is using the normal approximation

We need to check the conditions in order to use the normal approximation.

np=157*0.52=81.64  \geq 10

n(1-p)=157*(1-0.52)=75.36 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=157*0.52=81.64

\sigma=\sqrt{np(1-p)}=\sqrt{157*0.52(1-0.52)}=6.26

We want this probability:

P(X

And using the continuity correction we have this:

P(X

We can use the z score given by this formula Z=\frac{x-\mu}{\sigma}.

P(X< 76.5)=P(\frac{X-\mu}{\sigma}< \frac{76.5-81.64}{6.26})=P(Z < -0.821)=0.206

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<u>2nd method:-</u>

We have to choose 2 lines from 35 lines.

We can do it in 35_{C} _{2} ways = 595 points

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