For the first one,
294 + 30 + x- 37 = 360
add like terms
287 + x = 360
subtract 287 from both sides
x = 73
for the second one
4x +3 = 63
subtract 3 from both sides
4x = 60
divide both sides by 4
x = 15
First one is 75/100 = x/80 with 60 free throws, second best is 70/100 = x/80 with 56 free throws, and last is 65/100 = x/80 with 52 free throws
Answer:
2/3 is the answer. You could also put 0.6, which is the decimal form of 2/3
I hope this helps you!Step-by-step explanation:
Given:
It is given that,
PQ ⊥ PS and
∠QPR = 7x-9
∠RPS = 4x+22
To find the value of ∠QPR.
Formula
As per the given problem PR lies between PQ and PS,
So,
∠QPR+∠RPS = 90°
Now,
Putting the values of ∠RPS and ∠QPR we get,
or, 
or, 
or, 
or, 
Substituting the value of in ∠QPR we get,
∠QPR = 
or, ∠QPR = 
Hence,
The value of ∠QPR is 40°.
to find the radius you divide the circumference by 2pi
area is pi times radius to the 2nd power
