Answer:
um i don't know this (i do im just lazy as heck)
Step-by-step explanation:
In the usual sense, it has no inverse function. Since it is not an injection (f(0)=f(2)=0), an inverse function would have to map 0 both to 0 and 2, and that’s impossible.
However, if you restrict the domain to [1,+oo> (to make it injective), and the codomain to [-1,+oo> (to make it surjective), then it has an inverse function, given by g(y)=1+sqrt(y+1).
1. 15
2. -7
32. 6
You should get Photomath for these simple questions.
Answer:
Complementary angles are angles that add up to 90°
To find the complementary angle for an angle of 70° subtract it from 90°
That's
90° - 70° = 20
Hope this helps
Since they want only the coordinates of the vertices. You only care about where the lines intersect, the greater than, less than signs are irrelevant.
Get each equation in 'y=mx+b' form
1) y = -x + 9
2) y = 2x-21
3) y = -4x +15
Now you can set any 2 equations equal to each other and solve for 'x'.
This will be the 'x' coordinate of the point where the 2 lines intersect.
You need 3 points, so you will need 3 different sets of 2 equations:
1) = 2)
2x -21 = -x+9
3x = 30
x = 10 -----> y = -(10)+9 = -1
1) = 3)
-x+9 = -4x+15
3x = 6
x = 2 -------> y = -(2) + 9 = 7
2) = 3)
2x - 21 = -4x+15
6x = 36
x = 6 ---------> y = 2(6) -21 = -9
Therefore the 3 intersecting points are:
(10,-1)
(2, 7)
(6, -9)
