Answer:
Step-by-step explanation:
Given that, the mean, , and the standard deviation, , of normally distributed exam score are :
Let represent the score on a randomly selected exam from this set
The z-score, for the randomly selected exam score x:
For 64<x<76, the range of z-score is
Now, from the z-score table, the value for z=-1 is the probability for x<64.
As the value for z=-1 is 0.15866, so
P(x<64)=0.15866.
Similarly, the value for z=0.67 is 0.84134, so
P(x<76)=0.84134
So,
Hence,