Answer:
x = -5, and y = -6
Step-by-step explanation:
Suppose that we have two equations:
A = B
and
C = D
combining the equations means that we will do:
First we multiply both whole equations by constants:
k*(A = B) ---> k*A = k*B
j*(C = D) ----> j*C = j*D
And then we "add" them:
k*A + j*C = k*B + j*D
Now we have the equations:
-x - y = 11
4*x - 5*y = 10
We want to add them in a given form that one of the variables cancels, so we can solve it for the other variable.
Then we can take the first equation:
-x - y = 11
and multiply both sides by 4.
4*(-x - y = 11)
Then we get:
4*(-x - y) = 4*11
-4*x - 4*y = 44
Now we have the two equations:
-4*x - 4*y = 44
4*x - 5*y = 10
(here we can think that we multiplied the second equation by 1, then we have k = 4, and j = 1)
If we add them, we get:
(-4*x - 4*y) + (4*x - 5*y) = 10 + 44
-4*x - 4*y + 4*x - 5*y = 54
-9*y = 54
So we combined the equations and now ended with an equation that is really easy to solve for y.
y = 54/-9 = -6
Now that we know the value of y, we can simply replace it in one of the two equations to get the value of x.
-x - y = 11
-x - (-6) = 11
-x + 6 = 11
-x = 11 -6 = 5
-x = 5
x = -5
Then:
x = -5, and y = -6
Answer:
The probability there will be between 280 and 360 column inches of classified advertisement
P(280≤X≤360) = P(-2≤Z≤2) = 0.9544
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean the population = 320
The standard deviation of the Population = 20
Let 'X' be the random variable in a normal distribution
Let 'X' = 280
Let 'X' = 360
<u><em>Step(iii):-</em></u>
The probability there will be between 280 and 360 column inches of classified advertisement
P(280≤X≤360) = P(-2≤Z≤2)
= P(z≤2) -P(z≤-2)
= P(z≤2)+P(z≤2)
= 2P(z≤2)
= 2×0.4772 ( from normal table)
= 0.9544
Answer:
D
Step-by-step explanation:
for example point (2,0) is one of the solutions.
=> x + 2y <4
2+ 2(0) = 2 => 2< 4 (true)
=> 3x – y > 2
3(2)-0= 6 => 6>2 (true)
so, the option D is the correct one
we know the first term is -10, and the common difference is -2
-10
-10 - 2
-10 - 2 - 2
-10 - 2 - 2 - 2
-10 - 2 - 2 - 2 - 2
and so on.
"The equals sign with the squiggly line above it is the sign for congruence."
Therefore, GHIJ is congruent to PQRO.
H is then known as 99°;
J as 85°;
R as 123°;
P as 53°;
and all of the sides' km as listed.
If I'm understanding the question correctly, it is asking you for the appropriate degree of J, which we see as 85°.
Hope this helped!
