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suter [353]
3 years ago
5

80 POINTS!!!!!!

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
6 0
Plz dont be mean to me i just wanna understand and also its the blue line for answer 1
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There are 24 muffins in a bakery. If 3/8 of the muffins are blueberry, how many muffins are blueberry?
alex41 [277]

Answer:

9

Step-by-step explanation:

3/8 = 0.375

0.375(24) = 9

5 0
3 years ago
Read 2 more answers
Would you please help me? Thanks.
Butoxors [25]
The best answer is D.

According to the pythagorean theorem, a^2+b^2=c^2 in a right triangle where a and b are the legs and c is the hypotenuse.

The diagram given gives the length of both legs, so plug it into the equation to get c^2= 24^2+45^2
7 0
3 years ago
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Find the slope of the line passing through the points (-6, 6) and (4. – 7).
postnew [5]

Answer:

\displaystyle -\frac{13}{10}

Step-by-step explanation:

To solve this problem, first you have to use the slope formula of \displaystyle \frac{y_2-y_1}{x_2-x_1}.

y2= (-7)

y1=6

x2=4

x1(-6)

Solve.

\displaystyle \frac{(-7)-6}{4-(-6)}=\frac{-13}{10}=\boxed{-\frac{13}{10}}

Therefore, the correct answer is -13/10.

6 0
3 years ago
Read 2 more answers
PLEASE HELP WILL MARK BRAINLIEST
Romashka [77]

Answer:

A.The mean would increase.

Step-by-step explanation:

Outliers are numerical values in a data set that are very different from the other values. These values are either too large or too small compared to the others.

Presence of outliers effect the measures of central tendency.

The measures of central tendency are mean, median and mode.

The mean of a data set is a a single numerical value that describes the data set. The median is a numerical values that is the mid-value of the data set. The mode of a data set is the value with the highest frequency.

Effect of outliers on mean, median and mode:

  • Mean: If the outlier is a very large value then the mean of the data increases and if it is a small value then the mean decreases.
  • Median: The presence of outliers in a data set has a very mild effect on the median of the data.
  • Mode: The presence of outliers does not have any effect on the mode.

The mean of the test scores without the outlier is:

   \bar{x}=\frac{Total of the observations-Outlier value}{n-1} \\=\frac{(86*16)-72}{15} \\=\frac{1304}{15}\\ =86.9333

*Here <em>n</em> is the number of observations.

So, with the outlier the mean is 86 and without the outlier the mean is 86.9333.

The mean increased.

Since the median cannot be computed without the actual data, no conclusion can be drawn about the median.

Conclusion:

After removing the outlier value of 72 the mean of the test scores increased from 86 to 86.9333.

Thus, the the truer statement will be that when the outlier is removed the mean of the data set increases.

4 0
3 years ago
The following formula relates three quantities Force (F) mass (m) and acceleration (a).
Agata [3.3K]

a. F = ma

F/a = ma/a

m = F/a

b. F = ma

-30 = -6a

a = 5

c. F = ma

30 = 10a

a = 3

4 0
3 years ago
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