All categories

3 years ago

Task 1

Mathematics

1 answer:

AleksAgata [21]3 years ago

6 0

Answer:

123

Step-by-step explanation:

You might be interested in

Suppose that g(x) = f(x) + 5. Which statement best compares the graph of

CaHeK987 [17]

Answer:

Step-by-step explanation:

this is because your adding 5 to f(x) which would be x not y (pretty sure) and g(x) is y. your not adding 5 to g(x) therefore not b. D and A would never be correct for this because that would be subtraction of 5

5 0

2 years ago

Please help and tell me why u got that answer, I will mark brainliest

gregori [183]

The answer is C

i think so

4 0

2 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago

Jan estimates that approximately 575 drops fill a 100 milliliter bottle estimate how much water her leaky faucet wastes in a yea

umka21 [38]

2742 liters approiximately

8 0

2 years ago

Read 2 more answers

√45 is the distance between which of the following complex numbers?

Schach [20]

Step-by-step explanation:

we don't see the complex numbers.

so, we cannot check their distances.

a suspicion, though.

sqrt(45) a distance between 2 complex numbers is

sqrt(a² + b²).

so,

a² + b² = 45

a nice combination of whole square numbers would be 6 and 3.

6² + 3² = 36 + 9 = 45

if that is the case, then that would mean one of the following committed numbers

6 + 3i

3 + 6i

-6 + 3i

6 - 3i

-6 - 3i

-3 + 6i

3 - 6i

-3 - 6i

one of these numbers must be the result of the subtraction of the 2 provided complex numbers.

remember

(a + bi) - (c + di) = a-c + (b-d)i

3 0

3 years ago