Answer:13
Step-by-step explanation:
Answer:
The maximal margin of error associated with a 95% confidence interval for the true population mean is 2.238.
Step-by-step explanation:
We have given,
The sample size n=42
The sample mean 
The population standard deviation 
Let
be the level of significance = 0.05
Using the z-distribution table,
The critical value at 5% level of significance and two tailed z-distribution is

The value of margin of error is




The maximal margin of error associated with a 95% confidence interval for the true population mean is 2.238.
Tanθ + cotθ = 1/sinθcos<span>θ
since we know that;
tan</span>θ = sinθ/cos<span>θ, and
cot</span>θ = cosθ/sin<span>θ
now when we add tan</span>θ and cot<span>θ and replace their values;
tan</span>θ + cot<span>θ=sin</span>θ/cosθ + cosθ/sin<span>θ
</span>For a common denominator to add those two fractions, the obvious choice is sinθ.cosθ , so
tanθ + cotθ = sin²θ/sinθcosθ + cos²θ/sinθcosθ =sin²θ + cos²θ / sinθcosθ
now we can use the identity that;
sin²θ + cos²θ = 1
So,
tanθ + cotθ = 1/sinθcosθ