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Dmitry [639]
3 years ago
11

PLEASEEEE HELPPP i can’t get it

Mathematics
1 answer:
sveta [45]3 years ago
8 0

Answer:

(-4, 2.5)

Step-by-step explanation:

-8/2=-4

5/2=2.5

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Use the given values of n= 93 and p= 0.24 to find the minimum value that is not significantly​ low, μ- 2σ ​, and the maximum val
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Answer:

The answer is "Option a".

Step-by-step explanation:

n= 93 \\\\p= 0.24\\\\\mu=?\\\\ \sigma=?\\\\

Using the binomial distribution: \mu = n\times p = 93 \times 0.24 = 22.32\\\\\sigma = \sqrt{n \times p \times (1-p)}=\sqrt{93 \times 0.24 \times (1-0.24)}=4.1186

In this the maximum value which is significantly​ low, \mu-2\sigma, and the minimum value which is significantly​ high, \mu+2\sigma, that is equal to:

\mu-2\sigma = 22.32 - 2(4.1186) = 14.0828 \approx 14.08\\\\\mu+2\sigma = 22.32 + 2(4.1186) = 30.5572 \approx 30.56

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