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juin [17]
3 years ago
13

6th grade math 5x - 2

Mathematics
2 answers:
natima [27]3 years ago
5 0

Answer: 3x

verry eazy just subtract and keep the x

Naddik [55]3 years ago
4 0

Answer:

-10

Step-by-step explanation:

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Misha Larkins [42]

1. (0, 1) , (2, -9) , (3, -14) , (-6, 31)

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3 years ago
Q.16 please<br> With steps
blsea [12.9K]

The equations

2x^2+9x-5=0

and

2\left(t-\dfrac12\right)^2+9\left(t-\dfrac12\right)-5=0

are really the same, we're just setting x=t-\dfrac12, or t=x+\dfrac12.

2x^2+9x-5=(2x-1)(x+5)=0\implies x=\dfrac12,x=-5

So we get

t=\dfrac12+\dfrac12=1,t=-5+\dfrac12=-\dfrac92

8 0
3 years ago
A radioactive isotope decays. The mass of the daughter atom is 4 less than the parent. What type of decay occurred? *
Anettt [7]

Answer:

<em>I dont know</em>

Step-by-step explanation:

6 0
3 years ago
Rachel has tossed a fair coin ten times. It landed heads up every time. Is this LIKELY?<br> Explain
serious [3.7K]

Answer: No

Step-by-step explanation:

Rachael getting a head every time she tosses a coin ten times is unlikely.

Theoretically, there will be some head and tails during the toss of the coin. Theoretically, there should be 5 heads after ten tosses of the coin.

To get exactly 10 heads during the tosses of coin, Rachel would need a larger trial to get a more accurate data.

6 0
3 years ago
Find the equation of a parabola with a focus at (0,-1) and a directrix at y = 4.
Anastasy [175]

Answer:

  y = -1/10x^2 +2.5

Step-by-step explanation:

The distance from focus to directrix is twice the distance from focus to vertex. The focus-directrix distance is the difference in y-values:

  -1 -4 = -5

So, the distance from focus to vertex is p = -5/2 = -2.5. This places the focus 2.5 units below the vertex. Then the vertex is at (h, k) = (0, -1) +(0, 2.5) = (0, 1.5).

The scale factor of the parabola is 1/(4p) = 1/(4(-2.5)) = -1/10. Then the equation of the parabola is ...

  y = (1/(4p))(x -h) +k

  y = -1/10x^2 +2.5

_____

You can check the graph by making sure the focus and directrix are the same distance from the parabola everywhere. Of course, if the vertex is halfway between focus and directrix, the distances are the same there. Another point that is usually easy to check is the point on the parabola that is even with the focus. It should be as far from the focus as it is from the directrix. In this parabola, the focus is 5 units from the directrix, and we see the points on the parabola at y=-1 are 5 units from the focus.

5 0
3 years ago
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