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mote1985 [20]
3 years ago
5

==-0['=98[=-6098979468039850-245[]7p76][5p6=??

Mathematics
1 answer:
uysha [10]3 years ago
5 0

Answer:

My brain hurt

Step-by-step explanation:

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Pagie deposited $490.28 in savings account that earns 3.7% simple interest. What is paiges account
IRINA_888 [86]
<span>$490.28 * (1.037)  = $508.42

answer
</span>$508.42
5 0
3 years ago
(3x - 1) (2x + 9 ) what is x
elixir [45]

Answer:

You can't figure it out.

You need the whole problem, the best I can do is simplify it:

Expand the polynomial using the FOIL method.

6 x ^2  +  25 x  −  9

Step-by-step explanation:

Have a nice day!

3 0
3 years ago
Precalculus please help
JulijaS [17]

Answer:

amplitude = 2

period = 4

midline = y = -1

equation = either 2sin(\frac{pi}{2}x+\frac{pi}{2}  )-1 or 2sin(\frac{pi}{2}(x+1) )-1 depending on what format you're using

Step-by-step explanation:

the amplitude is the distance from the bottommost point to the topmost point

so if we use the points (0,1) and (2,-3), the min y value is -3 and the max y value is 1

so amplitude = ymax - ymin = 1 - - 3 = 4

amplitude = 4

the period is the distance it takes to complete one cycle

we have (0,1) and (4,1) which are two crest points

the distance between these is x2 - x1 = 4 - 0 = 4

period = 4

the midline is a horizontal line bisecting the sin line, which would be in the middle of its min and max y values

we already found that ymax = 1 and ymin = -3

so the midline would be y = (ymax + ymin) / 2 = (1 -3) /2 = -1

midline = y = -1

to find the sin equation, we will fill out the equation

asin(b(x-d))+c

a is the amplitude = 2

b = 2π/period = 2π/4 = π/2

c is the vertical shift. the midline of sine is originally at y = 0

since it is at y = -1 here, the vertical shift is -1 - 0 = -1

d is the horizontal shift. the middle of the upwards portion of the sine graph is originally at x = 0, but in the picture we see that it is at x = -1 so the shift is -1 - 0 = -1

a = 2, b = π/2, c = -1, d = -1

plug these values into the equation to get

asin(b(x-d))+c

2sin(π/2(x--1))+-1

=2sin(π/2(x+1))-1

=2sin(πx/2+π/2)-1

equation = either 2sin(\frac{pi}{2}x+\frac{pi}{2}  )-1 or 2sin(\frac{pi}{2}(x+1) )-1 depending on what format you're using

4 0
3 years ago
Can anyone help I could really use it
slamgirl [31]

Answer:

-12m-6n

Step-by-step explanation:

Let's break this down systematically

Start:

8m + 2n - 4(5m - 2n)

Use the distributive property

8m + 2n - <u>4(5m - 2n)</u>

8m + 2n - 20m - 8n

Match like terms <em>m </em>and <em>n</em>

8m - 20m = -12m

2n - 8n = -6n

<u>-12m-6n</u>

8 0
4 years ago
You need to wrap a rectangular box for christmas, where the length of the box is four times the width. suppose you have 500 squa
jekas [21]
<span>Width = 4.56 inches Length = 18.26 inches Height = 7.30 inches The box has 6 sides that needs to be covered, so let's create an equation to express the total surface area of the box. A = 2*w*l + 2*w*h + 2*h*l Now since we know that the length is 4 times the width, let's substitute 4w for l in the above equation and simplify. A = 2*w*4w + 2*w*h + 2*h*4w A = 8*w^2 + 2*w*h + 8*h*w A = 8*w^2 + 2*h*w + 8*h*w A = 8*w^2 + 10*h*w A = 2w(4w + 5h) And now since the area has to be 500, let's express h in terms of W. Substitute 500 for A and then solve for h. A = 2w(4w + 5h) 500 = 2w(4w + 5h) 250/w = 4w + 5h 250/w - 4w = 5h (250/w - 4w)/5 = h 50/w - (4/5)w = h So we now can calculate l (length) and h (height) of the box in terms of w. The equation for the volume is: V = lwh Let's substitute 4w for l V = lwh V = 4wwh V = 4hww V = 4hw^2 And substitute (50/w - (4/5)w) for h V = 4hw^2 V = 4(50/w - (4/5)w)w^2 V = (200/w - (16/5)w)w^2 V = 200w - (16/5)w^3 Now since we're looking for the largest possible volume, that should bring to mind "first derivative". We can use the power rule to calculate that easily. V = 200w - (16/5)w^3 V' = 200 - 3(16/5)w^2 V' = 200 - (48/5)w^2 Now the minimum and maximum values of V can only happen where V' equal 0. So let's set it to 0 and calculate w. V' = 200 - (48/5)w^2 0 = 200 - (48/5)w^2 (5/48)*(48/5)w^2 = (5/48)*200 w^2 = 1000/48 = 125/6 w = (5/6)sqrt(30), approximately 4.564354646 Now let's calculate length and height. l = (5/6)sqrt(30) * 4 = 18.25741858 h = 50/w - (4/5)w = 50/((5/6)sqrt(30)) - (4/5)((5/6)sqrt(30)) = 7.302967433 Rounding to 2 decimal places gives w=4.56, l=18.26, h=7.30</span>
8 0
4 years ago
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