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alexgriva [62]
3 years ago
6

Help Ill make you the brainiest ?!!

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
6 0

Answer:

h is the x-coordinate of the vertex

-1.5

Step-by-step explanation:

we have:

<em>f (x) = |x- h| + k</em>

In this function

The point  represent the vertex of the functionso

h is the x-coordinate of the vertex

k is the y-coordinate of the vertex

The answer will be -1.5

Hope this helps you!!

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What is the growth factor associated with the following growth rate: 30% decrease
fenix001 [56]

Given:

Growth rate = 30% decrease

To find:

The growth factor associated with the given growth rate.

Solution:

The general exponential function is:

y=a(1+r)^x

y=a(b)^x

Where, a is the initial value, r is the growth rate in decimal and b=1+r is the growth factor.

It is given that the growth rate is 30% decrease. So,

r=-30\%

r=-\dfrac{30}{100}

r=-0.3

Now,

b=1+r

b=1+(-0.3)

b=1-0.3

b=0.7

Therefore, the growth factor is 0.7.

5 0
3 years ago
For each expression, combine like terms and write an equivalent expression with fever terms.
ASHA 777 [7]

Answer:

1. 7x

2. 8x - 1

3. 6x + 12

4. 3x + 4

5. 13x - 7

Step-by-Step Explanation:

Hope this helps!

7 0
3 years ago
Read 2 more answers
Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i
jenyasd209 [6]

Answer:

If the limit that you want to find is \lim_{x\to \infty}\dfrac{P(x)}{Q(x)} then you can use the following proof.

Step-by-step explanation:

Let P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0} and Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0} be the given polinomials. Then

\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}

Observe that

\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}

and

\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}

Then

\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}

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3 years ago
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umka21 [38]
We should find the original number, 7 of 1/10. We divide the known number for the numerator, than multiply for denominator.

7 : 1 = 7 * 10 = 70 <- answer

So 7 is 1/10 of 70

We can check our work:

1/10 of 70 = 7?

70 : 10 = 7*1 = 7
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