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Akimi4 [234]
2 years ago
12

3% percent of the students at Lincoln High School are in orchestra, 5%

Mathematics
1 answer:
MissTica2 years ago
8 0

Answer:

The probability of a student to be in the orchestra or the band is 0.07 or 7%.

Step-by-step explanation:

The probability of a student to be in the orchestra or the band is given by the following formula:

p(orchestra or band) = p(orchestra) + p(band) - p(orchestra and band)

p(orchestra or band) = 0.03 + 0.05 - 0.01

p(orchestra or band) = 0.08 - 0.01

p(orchestra or band) = 0.07

The probability of a student to be in the orchestra or the band is 0.07 or 7%.

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What is the value of 21 + 6² - (35 - 8) ×3? A. 90 B. 0 C. -24 D. -54
zalisa [80]

Answer:

C. -24

Step-by-step explanation:

Hello!

To solve this we have to follow the order of PEMDAS

Parenthesis, exponents, multiplication and division, addition and subtraction

21 + 6^{2} - (35 - 8) * 3

Parenthesis first

21 + 6^{2} - (27) * 3

Exponents next

21 + 36 - 27 * 3

Multiplication and division from left to right

21 + 36 - 81

Addition and subtraction from left to right

57 - 81 = -24

The answer is C.-24

Hope this helps!

7 0
3 years ago
Read 2 more answers
The 4 in the tens place is what value of the 4 in the hundreds place
egoroff_w [7]

The 4 in the tens place is 1/10  of the value of the 4 in the hundreds place.

4 in the tens place = 40   4 in the hundreds place = 400

400/40 = 10 

so each 4 in the tens place is 1/10 of the value in the hundreds place

8 0
3 years ago
5(n+3)+4n<br> Simply the expression
dezoksy [38]
5(n + 3) + 4n

5n + 15 + 4n     Distributive property

5n + 4n = 9n      Combine like terms

9n + 15                Final answer

Answer:  9n + 15

8 0
3 years ago
Read 2 more answers
Three businesswomen are trying to convene in Northwest Arkansas for a business meeting. The first (Woman 1) is arriving on a fli
boyakko [2]

Answer:

a) The probability mass function of X is then presented in the table below.

X | probability P(X=x) or p

0 | 0.001

1 | 0.032

2 | 0.283

3 | 0.684

b) The cumulative distribution function of X

Cdf = Σ pdf = P(X=0) + P(X=1) + P(X=2) + P(X=3)

= 1.000

c) The probability that at least two businesswomen arrive on time

P(X ≥ 2) = P(X=2) + P(X=3) = 0.967

d) Expected value of X = E(X) = 2.65

e) Standard deviation = 0.545

Step-by-step explanation:

The probability that the woman coming from Atlanta arrives on time = P(A) = 0.90

The probability that the woman coming from Atlanta DOES NOT arrive on time = P(A') = 1 - 0.90 = 0.10

The probability that the woman coming from Dallas arrives on time = P(B) = 0.95

The probability that the woman coming from Dallas DOES NOT arrive on time = P(B') = 1 - 0.95 = 0.05

The probability that the woman coming from Chicago arrives on time = P(C) = 0.80

The probability that the woman coming from Chicago DOES NOT arrive on time = P(C') = 1 - 0.80 = 0.20

Since X is the random variable that represents how many women arrive on time,

To evaluate the probability function, we will first obtain the probability that the number of women that arrive in time = 0, 1, 2, and 3.

First probability; that no woman arrives on time. X = 0

P(X=0) = P(A') × P(B') × P(C')

= 0.10 × 0.05 × 0.20

P(X=0) = 0.001

Second probability; that only one of the women arrive on time. X = 1

P(X=1) = [P(A) × P(B') × P(C')] + [P(A') × P(B) × P(C')] + [P(A') × P(B') × P(C)]

= [0.90 × 0.05 × 0.20] + [0.10 × 0.95 × 0.20] + [0.10 × 0.05 × 0.80]

= 0.009 + 0.019 + 0.004

P(X=1) = 0.032

Third probability; that only two women arrive on time. X = 2

P(X=2) = [P(A) × P(B) × P(C')] + [P(A) × P(B') × P(C)] + [P(A') × P(B) × P(C)]

= [0.90 × 0.95 × 0.20] + [0.90 × 0.05 × 0.80] + [0.10 × 0.95 × 0.80]

= 0.171 + 0.036 + 0.076

P(X=2) = 0.283

Fourth probability; that all 3 women arrive on time. X = 3

P(X=3) = P(A) × P(B) × P(C)

= 0.90 × 0.95 × 0.8

P(X=3) = 0.684

The probability mass function of X is then presented in the table below.

X | probability P(X=x) or p

0 | 0.001

1 | 0.032

2 | 0.283

3 | 0.684

b) The cumulative distribution function of X

Cdf = Σ pdf = P(X=0) + P(X=1) + P(X=2) + P(X=3)

= 0.001 + 0.032 + 0.283 + 0.684 = 1.000

c) The probability that at least two businesswomen arrive on time

P(X ≥ 2) = P(X=2) + P(X=3) = 0.283 + 0.684 = 0.967

d) Expected value of X

Expected value is given as

E(X) = Σ xᵢpᵢ

E(X) = (0)(0.001) + (1)(0.032) + (2)(0.283) + (3)(0.684) = 0 + 0.032 + 0.566 + 2.052 = 2.65

e) What is the standard deviation of X?

Standard deviation = √(variance)

Variance = Var(X) = Σx²p − μ²

μ = E(X) = 2.65

Σx²p = (0²)(0.001) + (1²)(0.032) + (2²)(0.283) + (3²)(0.684)

= (0)(0.001) + (1)(0.032) + (4)(0.283) + (9)(0.684)

= 0 + 0.032 + 1.132 + 6.156

= 7.32

Variance = Var(X) = 7.32 - 2.65² = 7.32 - 7.0225

Var(X) = 0.2975

Standard deviation = √(variance) = √0.2975

Standard deviation = 0.545

Hope this Helps!!!

8 0
3 years ago
I’ll give Brainly est help. B
natulia [17]

Answer:

C) 99 + 3x

Step-by-step explanation:

Since it's always going to cost 99, it'll stay like that since it's a constant

Since it's 3 PER person, that means 3 will have a variable: 3x

5 0
3 years ago
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