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Lana71 [14]
3 years ago
7

9. PLEASE HELP ME

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
8 0

Answer:

C. (3, 3)

Step-by-step explanation:

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(-10, -7), (-8, 1)<br> Distance between
liubo4ka [24]

Answer:9

Step-by-step explanation

√(x2-x1)^2 +(y2-y1)^2

√(-7-(-10)^2 +(1-(-8)^2

√(-7+10)^2 + (1+8)^2

√(3)^2 +(9)^2

√(9+81)

√90

=9.48

Approximately 9

7 0
4 years ago
A force vector M points 3 N in the x-direction and 4 N in the y-direction. What is Vector M’s magnitude?
julsineya [31]

Answer:

5 N.

Step-by-step explanation:

Given that,

A force vector M points 3 N in the x-direction and 4 N in the y-direction.

We need to find the magnitude of vector M. The magnitude of the vector when they are perpendicular to each other is given by :

M=\sqrt{3^2+4^2} \\\\M=5\ N

So, the required magnitude of M is 5 N.

8 0
3 years ago
30<br> 20<br> Find y.<br> I don’t get thisss
Allisa [31]
Y=10. Hopefully this picture explains it

7 0
3 years ago
It is 2.1 kilometers from Yoko's house to the nearest mailbox. How far is it in meters?
Galina-37 [17]

Answer:

2100 m

Step-by-step explanation:

1 km = 1000 meters

2.1 km = 2100 meters

7 0
4 years ago
A stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer. If the top laye
Svetlanka [38]

Answer:  The total number of logs in the pile is 6.

Step-by-step explanation:  Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two​ logs.

We are to find the total number of logs in the pile.

Let n represents the total number of logs in the pile.

Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with

first term, a = 32  and  common difference, d = -6.

We know that

the n-th term of an arithmetic sequence with first term a and common difference d is

a_n=a+(n-10)d.

Since there are n logs in the pile, so we get

a+(n-1)d=2\\\\\Rightarrow 32+(n-1)(-6)=2\\\\\Rightarrow 32-6n+6=2\\\\\Rightarrow 6n=36\\\\\Rightarrow n=6.

Thus, the total number of logs in the pile is 6.

6 0
3 years ago
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