Question

A force vector M points 3 N in the x-direction and 4 N in the y-direction. What is Vector M’s magnitude?

Answer 1

Answer:

5 N.

Step-by-step explanation:

Given that,

A force vector M points 3 N in the x-direction and 4 N in the y-direction.

We need to find the magnitude of vector M. The magnitude of the vector when they are perpendicular to each other is given by :

$M=\sqrt{3^2+4^2} \\\\M=5\ N$

So, the required magnitude of M is 5 N.