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Phantasy [73]
3 years ago
8

Which number line shows the solution of –5x + 10 > –15?

Mathematics
2 answers:
Reil [10]3 years ago
4 0

Answer:

b

Step-by-step explanation:

Harlamova29_29 [7]3 years ago
3 0

Answer:

Where is the number line?? ;-;

Step-by-step explanation:

Dude I cant answer if you dont show me the number lines

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The perimeter of the rectangular pool is 80 feet.The length of the pool is 10 feet more than twice of the width.Find the length
AveGali [126]
Width= 10
Length= 30

Explanation: photo

7 0
3 years ago
A raft and a motorboat simultaneously leave from the same point and move down the river. After 2 hours the motorboat turns aroun
lesya692 [45]

Answer:

2 hours

Step-by-step explanation:

Let x mph be the speed of motorboat in still water and y mph be the speed of current.

A raft and a motorboat simultaneously leave from the same point and move down the river, then speeds down the river are:

        motorboat =  x + y mph

        raft = y mph

In two hours they will cover:

        motorboat = 2(x+y) miles

        raft = 2y miles

After 2 hours the motorboat turns around and starts moving towards the raft (against the current), so its speed is now x - y mph.

Let t be the time they move towards each other. In t hours, they cover

        motorboat = t(x - y) miles

        raft = ty miles

The distance from the starting point to the turning point is the same as the sum of the distances the raft covers and the motorboat covers after turning around, so

2(x+y)=2y+t(x-y)+ty \\ \\2x+2y=2y+tx-ty+ty\\ \\2x=tx\\ \\t=2\ hours

6 0
3 years ago
Using properties of sets show that : a) A ∩ (A’ U B) = A ∩ B b) A ∩ (A U B )’ = Ф
asambeis [7]

Answer:

a) From A ∩ A' = ∅, we have;

A ∩ (A' ∪ B) = A ∩ B

b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have

A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

A ∩ A' = ∅ (complementary law of sets)

Therefore;

(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B)  = (A ∩ B) (Addition to zero identity property)

∴  A ∩ (A' ∪ B) = A ∩ B

b) By De Morgan's law

(A ∪ B)' = A' ∩ B'

Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')

By associative law of sets, we have;

A ∩ (A' ∩ B') = (A ∩ A') ∩ B'

A ∩ A' = ∅ (complementary law of sets)

Therefore, (A ∩ A') ∩ B' = ∅  ∩ B' = ∅

Which gives;

A ∩ (A ∪ B)' = ∅.

4 0
3 years ago
In 2013, a study found that U.S. consumers consumed soft drinks with a mean of 42.2 gallons per year and variance of 169. Ninety
melisa1 [442]

Answer:

Ninety-five percent of consumers in the U.S. consumed less than 63.59 gallons.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The standard deviation is the square root of the variance, so \sigma = \sqrt{169} = 13

Also, the mean is 42.2, so \mu = 42.2

Ninety-five percent of consumers in the U.S. consumed less than how many gallons?

The 95th percentile, which is the value of X when Z has a pvalue of 0.95. So X when Z = 1.645

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 42.2}{13}

X - 42.2 = 13*1.645

X = 63.59

Ninety-five percent of consumers in the U.S. consumed less than 63.59 gallons.

4 0
3 years ago
4. Nick wants to buy a bike that cost $195. If he waits one more month, the bike will be discounted by 40%. How much money will
mr Goodwill [35]
4. nick will save $78
4 0
3 years ago
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