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2 years ago

Classify the real number. List all the subsets in which the number belongs

Mathematics

1 answer:

Natali [406]2 years ago

6 0

Arithmetic

This number is rational.

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A central angle of a circle measures 1.5 radians. If the radius of the circle is 3 cm, what is the area of the related sector?

soldi70 [24.7K]

Answer:

Option B. $6.75\ cm^{2}$

Step-by-step explanation:

we know that

The area of a circle is equal to

$A=\pi r^{2}$

we have

$r=3\ cm$

substitute

$A=\pi (3^{2})=9 \pi\ cm^{2}$

Remember that

$2\pi$ radians subtends the complete circle of area $9 \pi\ cm^{2}$

by proportion

Find the area of the related sector for a central angle of $1.5$ radians

Let

x------> the area of the related sector

$\frac{9 \pi}{2\pi}\frac{cm^{2}}{radians} =\frac{x}{1.5}\frac{cm^{2}}{radians}\\ \\x=9*1.5/2\\ \\x= 6.75\ cm^{2}$

7 0

3 years ago

If f(x) = x/2 - 3 an g(x) = 3x^2 + x-6, find (f+g)(x)

PilotLPTM [1.2K]

Answer:

(f + g)(x) = 3x^2 + 3x/2 - 9

Step-by-step explanation:

In order to find a composite function through addition, you simply add the two equations together.

f(x) + g(x)

x/2 - 3 + 3x^2 + x - 6

3x^2 + 3x/2 - 9

4 0

3 years ago

F(n+1)=f(n)-3 f(1)=15

Trava [24]

Answer:

f(n+1) = 13

Step-by-step explanation:

We know that f(1) = 15
So we can substitute this for f(n)-3
With this:

f(n+1) = f(1) -3
f(n+1) = 15-2
f(n+1) = 13

5 0

3 years ago

Find the difference 78003-32136

deff fn [24]

The difference of 78003 and 32136 is 45867

Hope this helped!!!!!

5 0

3 years ago

Read 2 more answers

Assume that the population proportion is 0.56. Compute the standard error of the proportion, σp, for sample sizes of 100, 200, 5

Aliun [14]

Answer:

Standard errors are 0.049, 0.035, 0.022, and 0.016.

Step-by-step explanation:

The given value of population proportion (P) = 0.56

Given sample sizes (n ) 100, 200, 500, and 1000.

Now standard error is required to calculate.

Use the below formula to find standard error.

When sample size is n = 100

$\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{100}} =0.049$

When sample size is n = 200

$\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{200}} = 0.035$

When sample size is n = 500

$\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{500}} =0.022$

When sample size is n = 1000

$\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{1000}} = 0.016$

4 0

3 years ago