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nikitadnepr [17]
3 years ago
12

If the product of two positive fractions a and b is 15/56, find three pairs of possible values for a and b

Mathematics
1 answer:
Andrews [41]3 years ago
4 0

Answer:

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

Step-by-step explanation:

According to the question,

a x b = 15/56

three possible pairs will be as follows:

Before proceeding to make possible pairs, we have to know the prime factorization of the numbers -

15 = 1, 3, 5, 15

56 = 1, 2, 4, 7, 8, 14, 28, 56

As we need three possible pairs, we have to check which pairs take us to 15/56. Again, since the fraction is positive, therefore, the fractions will be proper. Therefore, 3/2, or 5/4 will not be counted. Therefore,

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

fourth possible pairs = (3/8)*(5/7) = 15/56

So, we can get those four possible pairs. Among those, first 3 pairs are different. Therefore, those are possible pairs.

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Step-by-step explanation :

Dado que Conner y Jana se multiplican (3568)(39610). El trabajo de Conner El trabajo de Jana (3568)(39610) = 35 + 968 + 10 = 314618 (3568)(39610) = 35⋅968⋅10 = 345680 ¿Es correcto cualquiera de ellos?

Jana y Conner están multiplicando dos números dados. Así que la pregunta es

                                 3568 x 39610

                                  0000

                                3568x

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                --------------------------------------

                           141328480

Así que la respuesta correcta es 141328480.

También los números se pueden agrupar como

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Después de agrupar multiplicando ambos términos obtenemos la respuesta requerida.

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