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3 years ago

Onetta biked 325 miles in 5 days. If she biked the same number of miles each day, how far did she bike each day help moi plz

Mathematics

1 answer:

Strike441 [17]3 years ago

3 0

She did 65 miles each day so 325÷5=65 she did each day

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Quadrilateral QRST, with vertices Q (1, 2), R (3, 4), S (5, 6), and T (2, 7), is dilated by a factor of 2 with the center of dil

bija089 [108]

Answer:

Step-by-step explanation:

Given

Quadrilateral QRST

Q (1, 2), R (3, 4), S (5, 6), and T (2, 7)

Dlated Factor = 2

Required

Coordinates of quadrilateral Q′R′S′T′

Provided that a quadrilateral is dilated with the center of dilation at the origin; the new dilated shape is simply the multiplication of the dilation factor by the coordinates of the original shape;

In other words,

Q'R'S'T' = Dilation factor * QRST

When Q = (1,2)

Q' = 2 * (1,2)

Q' = (2,4)

When R = (3,4)

R' = 2 * (3,4)

R' = (6,8)

When S = (5,6)

S' = 2* (5,6)

S' = (10,12)

When T= (2,7)

T' = 2 * (2,7)

T' = (4,14)

Hence, the coordinates of Q'R'S'T' is

Q' = (2,4); R' = (6,8); S' = (10,12); T' = (4,14)

6 0

3 years ago

FG ∥ CB, A ∈ FG, D ∈ AB, E ∈ AC

andrey2020 [161]

Answer:

The value of x is $31^{\circ}$ .

Step-by-step explanation:

Please look at the figure attached to get more clear solution.

We have given:

FG||CB

And the line that cut the parallel line is transversal so, here BA is transversal

And alternate interior angles on transverse line are equal

So, ∠1=∠4

And ∠4= $28^{\circ}$

Hence, ∠1=∠4= $28^{\circ}$

And On FG the sum of angles will be $180^{\circ}$

∠3+∠2+∠1= $180^{\circ}$

$90^{\circ}$ +∠2+ $28^{\circ}$ = $180^{\circ}$

Hence, ∠2= $62^{\circ}$

Now, we know that the sum of interior angles is equal to the exterior angle:

Therefore, ∠2+∠5=∠6+∠7

$62^{\circ}+3x=x+4x$

On simplification we get:

$2x=62^{\circ}$

$x=31^{\circ}$

Hence, the value of x is $31^{\circ}$ .

3 0

3 years ago

Point S is on line segment R T ‾ RT . Given R S = 4 x − 10 , RS=4x−10, S T = 2 x − 10 , ST=2x−10, and R T = 4 x − 4 , RT=4x−4, d

mylen [45]

Question not well presented

Point S is on line segment RT . Given RS = 4x − 10, ST=2x−10, and RT=4x−4, determine the numerical length of RS

Answer:

The numerical length of RS is 22

Step-by-step explanation:

Given that

RS = 4x − 10

ST=2x−10

RT=4x−4

From the question above:

Point S lies on |RT|

So, RT = RS + ST

Substitute values for each in the above equation to solve for x

4x - 4 = 4x - 10 + 2x - 10 --- collect like terms

4x - 4 = 4x + 2x - 10 - 10

4x - 4 = 6x - 20--- collect like terms

6x - 4x = 20 - 4

2x = 16 --- divide through by 2

2x/2 = 16/2

x = 8

Since, RS = 4x − 10

RS = 4*8 - 10

RS = 32 - 10

RS = 22

Hence, the numerical length of RS is calculated as 22

8 0

3 years ago

70% of a number is 98.

hammer [34]

The solution is as follows:

Set up the proportion:

70% - 98
90% - x

70% / 90% = 98 / x

7 / 9 = 98 /x

(7 / 9) x = 98

x = 98 x 9/7

x = 14 x 9

x = 126

The answer is D. 126.

I hope my answer has come to your help. God bless and have a nice day ahead!

8 0

3 years ago

There are 2 mixtures of light red paint.

Musya8 [376]

Mixture B is the right answer

8 0

3 years ago