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Veronika [31]
2 years ago
8

Onetta biked 325 miles in 5 days. If she biked the same number of miles each day, how far did she bike each day help moi plz

Mathematics
1 answer:
Strike441 [17]2 years ago
3 0
She did 65 miles each day so 325÷5=65 she did each day
You might be interested in
ASAP HELP!!
AVprozaik [17]
FIRST SOLUTION!
first number = x
second number = x+2
third number = x+4
fourth number=x+6
fifth number=x+8
sixth number=x+10
seventh number=x+12

add all of those up and combine like terms to get 7x+42=357. Now subtract 42 from both sides to get 7x=315. Next, divide both sides by 7 to get x=45. To get the numbers, plug in 45 for x.

Your numbers should be 45,47,49,51,53,55, and 57.
4 0
3 years ago
Read 2 more answers
Help, I wanna pass this iready lesson or im going to get yelled at.
densk [106]

Answer:

1/10 is the correct answer

Step-by-step explanation:

3/5=6/10

7/10-6/10=1/10

7 0
2 years ago
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Rita is starting a running program. The table shows the total number of miles she runs in different weeks. What is the equation
prisoha [69]

Answer:

The best fit line is y = 1.671x + 4.699

Step-by-step explanation:

We are given,

The table representing the number of miles run in different weeks is,

Week                        Miles Run

1                                        5

2                                       8

4                                       13

6                                       15

8                                       19

10                                     20

Using the linear regression calculator, we see that,

<h3>The equation of the line best fit for the data is y = 1.671x + 4.699.</h3>

6 0
3 years ago
Read 2 more answers
3<br> Select the correct answer.<br> What are the solutions to this equation?<br> 16x² + 9 = 25
Charra [1.4K]

Answer:

Step-by-step explanation:

16x^2 + 9 = 25

16x^2 = 16

x^2 = 1

x = 1, -1

4 0
3 years ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
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