Answer: The required probability is
Step-by-step explanation:
Since we have given that
Number of people came into Brad's store = 48
Number of them made a purchase = 40
So, the experimental probability that the next person to come into the store will make a purchase would be
Hence, the required probability is
Answer:
a. 0.563 = 56.3% probability that for the next 60 minutes (two time periods) the system will be in the delay state.
b. 0.625 = 62.5% probability that in the long run the traffic will not be in the delay state
Step-by-step explanation:
Question a:
The probability of finding a traffic delay in one period, given a delay in the preceding period, is 0.75.
The system currently is in traffic delay, so for the next time period, 0.75 probability of a traffic delay. If the next period is in a traffic delay, the following period will also have a 0.75 probability of a traffic delay. So
0.75*0.75 = 0.563
0.563 = 56.3% probability that for the next 60 minutes (two time periods) the system will be in the delay state.
b. What is the probability that in the long run the traffic will not be in the delay state? If required, round your answers to three decimal places.
If it doesn't have a delay, 85% probability of continuing without a delay.
If it has a delay, 75% probability of continuing with a delay.
So, for the long run:
x: current state
85% probability of no delay if x is in no delay, 100 - 75 = 25% if x is in delay(1-x). So
0.625 = 62.5% probability that in the long run the traffic will not be in the delay state