The general solution of <span>y' + 2xy = (x^3) is y(x) = c1e^(-x^2)
The general solution of </span><span>ydx = (y(e^y) - 2x)dy is x = c1/(y(x))^2 + (e^y(x) ((y(x))^2 - 2y(x) + 2)/(y(x))^2
</span>
The general solution of<span> (dP)/(dt) + 2tP = P + 4t - 2 is P(t) = c1e^(t - t^2) + 2</span>
13.01 < 13.1 because there is a 0 in the tenths place in 13.01 and there is a 1 in the tenths place in 13.1
Answer:
No
Step-by-step explanation:
plug (6,3) into the given equation to find out
3 = 4(6-5)
3 = 4(1)
3 = 4
since 3 does not equal 4, the point (6,3) does not satisfy the equation y=4(x-5)
Answer:
Congruent by ASA
Step-by-step explanation:
2 pairs of corresponding angles are given equal.
Also side DC is common to both triangles.
So the 2 triangles are congruent by ASA
