Answer:
Question 1 = c) Medium: 88 ft²
Question 2 = d) 46.7 ft³
Step-by-step explanation:
Question 1
We would be solving this question by finding the surface area of the tent. The shape of the tent is a square based pyramid.
The surface area of a square based pyramid(tent) =
a² + 2ah
Where in the diagram,
a = base length = 4 ft
h = height of the pyramid (tent ) = 9ft
Surface area = 4² + 2 × 4 × 9
= 16 + 72
= 88ft²
Therefore, the size tarp should she purchase is Medium: 88 ft²
Question 2
For question 2, from the attached diagram, we can see that the diagram is a square based pyramid.
To calculate the amount of water that would fill the square based pyramid, we would have to find the Volume of the tent(square based pyramid).
The formula for the Volume of the tent(square based pyramid) = 1/3(a²h)
Where a = base edge
h = height of the pyramid.
From the diagram,
a = base edge => 4ft.
From the question,
h = height of the tent is given as how tall the tent is = 8.75ft.
Therefore, 1/3(a²h)
1/3 × (4ft)²× 8.75ft
= 46.67ft³
Approximately = 46.7ft³
Therefore, the amount of water it would it take to fill the tent, if the tent is 8.75 ft tall is 46.7ft³
Answer:
7 1/8 or 7.125
Step-by-step explanation:
first subsitute z for 4
28/4 - 4/4 + 1 1/8
then do 28/4 - 4/4 which is 6,
add that to 1 1/8
and get 7 1/8
Check the picture below.
well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.
bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.
![\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}](https://tex.z-dn.net/?f=%5Cbf%20A%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B4%7D%29%5Cqquad%20B%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B1%7D%29%20~%5Chfill%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B1%7D-%5Cstackrel%7By1%7D%7B4%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B5%7D-%5Cunderset%7Bx_1%7D%7B1%7D%7D%7D%5Cimplies%20%5Ccfrac%7B-3%7D%7B4%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bslope%20of%20AB%7D%7D%7B-%5Ccfrac%7B3%7D%7B4%7D%7D%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Ctextit%7B%5Cunderline%7Bnegative%20reciprocal%7D%20and%20slope%20of%20the%20diameter%7D%7D%7B%5Ccfrac%7B4%7D%7B3%7D%7D)
so, it passes through the midpoint of AB,
so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)
Answer:
950, 1121.00, 1322.78, 1,560.88, 1,841.84
Step-by-step explanation:
Calculation to determine the sequences that describes his increasing monthly balance
Based on the information given in order for us to determine the sequence we have to multiply the amount owes by the interest rate and then add back the answer you got to the previous amount you multiplied the interest rate to.
First sequence will be the amount he owes on a credit which is $950
Second sequence
950 * .018 = 171.00
950 + 171.00 = 1121.00
Third sequence
1121.00 * .018 = 201.78
1121.00 + 201.78 = 1322.78
Fourth sequence
1322.78*0.18=238.10
1322.78+238.10=1,560.88
Last sequence
1,560.88*0.18=280.96
1,560.88+280.96=1,841.84
Therefore the sequences that describes his increasing monthly balance are:
950, 1121.00, 1322.78, 1,560.88, 1,841.84
