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Darya [45]
3 years ago
9

If there are 3 apples for every 4 oranges, how many apples would you have if you had 20 oranges?

Mathematics
2 answers:
Svetach [21]3 years ago
5 0

Answer:

I was kind of confused on this one but is it 15 apples?

Step-by-step explanation:

3, 6, 9, 12, 15

4, 8, 12, 16, 20

I think the answer is 15 apples.

Montano1993 [528]3 years ago
3 0

Answer:

6 Apples

Step-by-step explanation:

There would be six apples and 2 oranges left over.

Hope this Helps!

:D

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Find y when x=14 if y varies directly with x2 and y=72 when x=6
katovenus [111]

The approach is to first find the value of constant of proportionality 'k'.

As y varies directly with x²

So we have

y = k x².

Now when x = 6 , y = 72

Substituting the values we get

72 = k (6)²

72 = 36 k

Dividing by 36 on both sides

2 = k

So (1) becomes

y = 2 x²

Now we need to find y when x = 14

Substituting the values in (2) we get

y = 2 ×(14)²

y = 2 × 196

y =  392

Hence y = 392 when x = 14.

5 0
3 years ago
Read 2 more answers
3p-(-20)=50 what is p?
zlopas [31]
3p-(-20)=50

3p+20=50  subtract 20 from both sides

3p=30  divide both sides by 3

p=10
3 0
3 years ago
Read 2 more answers
What is z 15 = -45+ z
damaskus [11]

Answer:

60 = z

Step-by-step explanation:

15 = - 45 + z

15 + 45 = z

60 = z

8 0
3 years ago
Pete is a politician. He claims that 32% of the households in his district have total household incomes below the poverty level.
victus00 [196]

Answer:

z=\frac{0.3867 -0.32}{\sqrt{\frac{0.32(1-0.32)}{225}}}=2.145  

For a bilateral test the p value would be:  

p_v =2*P(z>2.145)=0.0320  

Step-by-step explanation:

Information given

n=225 represent the sample selected

X=87 represent the households with incomes below the poverty level

\hat p=\frac{87}{225}=0.3867 estimated proportion of households with incomes below the poverty level

p_o=0.32 is the value that we want to test

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to check if the true proportion is equal to 0.32 or not.:  

Null hypothesis:p=0.32  

Alternative hypothesis:p \neq 0.32  

The statistic is given bY:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.3867 -0.32}{\sqrt{\frac{0.32(1-0.32)}{225}}}=2.145  

For a bilateral test the p value would be:  

p_v =2*P(z>2.145)=0.0320  

4 0
3 years ago
Round 89,891 to the nearest ten-thousands place.
frez [133]
The ten thousands digit is the 8 to the left edge.

You need to increase this digit because the thousands digit is greater than zero.


The answer is 90,000.
6 0
3 years ago
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