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2 years ago

Solve for x on the interval 0≤x<2pi cos(3x)=1/2

Mathematics

1 answer:

Ede4ka [16]2 years ago

7 0

We will see that the solution in the given interval is: x = 0.349 radians.

<h3>How to solve equations with the variable in the argument of a cosine?</h3>

We want to solve:

cos(3*x) = 1/2

Here we must use the inverse cosine function, Acos(x). Remember that:

cos(Acos(x)) = Acos(cos(x)) = x.

If we apply that in both sides, we get:

Acos( cos(3x) ) = Acos(1/2)

3*x = Acos(1/2)

x = Acos(1/2)/3 = 0.349

So x is equal to 0.349 radians, which belongs to the given interval.

If you want to learn more about trigonometry, you can read:

brainly.com/question/8120556

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Answer:

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Step-by-step explanation:

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x = - 2 - 2/3 + 1/4
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2 years ago

Let A be the area of a circle with radius r. If dr/dt=3, find dA/dt when r=2.

astraxan [27]

$\bf \textit{area of a circle}=A=\pi r^2
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3 years ago

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Aleks [24]

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Step-by-step explanation:

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2 years ago

A walking path across a park is represented by the equation y=-3x - 3.A

kifflom [539]

Answer:

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Step-by-step explanation:

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The point-slope form of the equation for a line can be used to write the equation for the new path:

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Math question Informatin in dot plots

kozerog [31]

Answer:

Step-by-step explanation:

Range = difference between the highest and the lowest

Mode = Data that occurs the most time

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1) Range = 28 -21 = 7

Mode = 25

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Median = average of 7th and 8th term

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2 years ago