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2 years ago

Solve for x on the interval 0≤x<2pi cos(3x)=1/2

Mathematics

1 answer:

Ede4ka [16]2 years ago

7 0

We will see that the solution in the given interval is: x = 0.349 radians.

<h3>How to solve equations with the variable in the argument of a cosine?</h3>

We want to solve:

cos(3*x) = 1/2

Here we must use the inverse cosine function, Acos(x). Remember that:

cos(Acos(x)) = Acos(cos(x)) = x.

If we apply that in both sides, we get:

Acos( cos(3x) ) = Acos(1/2)

3*x = Acos(1/2)

x = Acos(1/2)/3 = 0.349

So x is equal to 0.349 radians, which belongs to the given interval.

If you want to learn more about trigonometry, you can read:

brainly.com/question/8120556

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A rocket is shot off from a launcher. The accompanying table represents the height of the rocket at given times, where x is time

galben [10]

Answer:

The height at time of 12.1 seconds is approximately 729.2562 feet

Step-by-step explanation:

The general form of the quadratic regression equation is y = A + Bx + Cx²

The quadratic regression formula is given as follows;

$B = \dfrac{S_{xy}S_{x'x'}-S_{x'y}S_{xx'}}{S_{xx}S_{x'x'} -(S_{xx'})^2}$

$C = \dfrac{S_{x'y}S_{xx}-S_{xy}S_{xx'}}{S_{xx}S_{x'x'} -(S_{xx'})^2}$

$A = \bar y - B \bar x - C \bar {x^2}$

$S_{xx} = \Sigma (x_i - \bar x)^2$

$S_{xy} = \Sigma (x_i - \bar x)(y_i - \bar y)$

$S_{xx'} = \Sigma (x_i - \bar x)(x^2_i - \bar {x^2})$

$S_{x'x'} = \Sigma (x^2_i - \bar {x^2})^2$

$S_{x'y} = \Sigma (x^2_i - \bar {x^2})(y_i - \bar {y})$

Solving using an online quadratic regression calculator, gives;

A = 2.5643259

B = 246.6374865

C = -15.41986006

Substituting gives;

y = 2.5643259 + 246.6374865·x -15.41986006·x²

When time, x = 12.1, we have;

y = 2.5643259 + 246.6374865×12.1 -15.41986006×12.1²≈ 729.2562 feet

The height at time of 12.1 seconds ≈ 729.2562 feet.

8 0

3 years ago

Answer it all please

andre [41]

180 * 365 = 65700 litres/year
65700 / 1000 = 65.7 m^3/year
0.9122 * 65.7 = £59.932 for water used
28.20 + 59.93 = £88.13 for water meter annually

£88.13 < £107 so yes, he should have a water meter.

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3 years ago

The ratio of the sides of two similar octagons is 2:5. What is the ratio of the perimeters of these octagons?

Tom [10]

So we see the ratio of the sides of two similar octagons is 2:5 so let's say the first octagon has a side of 2 and the other has a side of 5. 2*8 = 16 and 5*8 = 40. 16:40 = 4:10 = and is again 2:5. So the answer is 2:5.

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3 years ago

What is the difference between defined and undefined terms?

rodikova [14]

Answer:

An undefined term is a term that can't be defined so easily. There really isn't a definition to define such terms. Consider the word "the." We use the word "the" all of the time, but do we really know how to define the word "the?" "Am" is another word that can't be defined so easily.

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3 years ago

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How do measurements of time differ for events in a frame of reference that moves at 50% of the speed of light relative to us? At

ZanzabumX [31]

Answer with explanation:

Relation between Speed , Distance and time

Distance =Speed × Time

→It means Speed is inversely Proportional to time.

As distance will remain constant , in that frame of reference

If speed of light in a Medium

$=s=3 \times 10^8 \frac{\text{meter}}{\text{second}}$

Then, time taken to cross the medium = t seconds or hours or another unit of time.

Now, If speed of light is 50% of the speed of light relative to us

That is Speed of light in another medium

$=w=\frac{50}{100} \times 3 \times 10^8\\\\=1.5 \times 10^8 \frac{\text{meter}}{\text{second}}$

Then, time taken to cross the medium = 2t seconds or hours or another unit of time.

Using Unitary Method

$\rightarrow v_{1}\times t_{1}=v_{2} \times t_{2}\\\\1.\rightarrow 3 \times 10^8 \times t=\frac{50}{100} \times 3 \times 10^8 \times t_{1}\\\\t_{1}=2t\\\\2.\rightarrow 3 \times 10^8 \times t=\frac{99.5}{100} \times 3 \times 10^8 \times t_{2}\\\\t_{2}=\frac{1000t}{995}\\\\t_{2}=\frac{200t}{199}$

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4 years ago

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