C = 2m^2 + m
D = 2 - 6m + 2m^2
2C = 2(2m^2 + m) = 4m^2+2m
2D = 2(2-6m+2m^2) = 4-12m+4m^2
2C - 2D =
4m^2+2m-(4-12m+4m^2) =
4m^2+2m-4+12m-4m^2 =
0m^2 + 14m -4 =
14m - 4
Answer:
<u>242 sq. cm.</u>
Step-by-step explanation:
<u>Surface Area</u>
- 2(LH + BH + LB)
- 2(10 × 3 + 7 × 3 + 10 × 7)
- 2(30 + 21 + 70)
- 2(121)
- <u>242 sq. cm.</u>
Answer:
Mark me as brainlist
Step-by-step explanation:
P = Perimeter
L = Length
W = Width
Perimeter of rectangle = L + L + W + W
or P = 2L + 2W
You know:
P = 36 inches
L = 2W [length is(=) 2 times it's width]
W = ?
P = 2L + 2W
Substitute/plug in what you know, plug in 2W for L since L = 2W
36 = 2(2W) + 2W Simplify
36 = 4W + 2W
36 = 6W Divide 6 on both sides
6 = W Now that you know the width, you can find the length:
L = 2W
L = 2(6)
L = 12
L = 12 in
W = 6 in
PROOF
P = 2(12) + 2(6)
P = 24 + 12
P = 36
Answer: A
2x^2+2x-8 is the quotient when x+3 divides P(x)
=> P(x) = (2x² + 2x -8)(x + 3) = 2(x² + x - 4)(x + 3) = (x² + x - 4) (2x + 6)
=> the quotient when 2x+6 divides p(x) is x² + x - 4
Step-by-step explanation:
I believe the correct answer from the choices listed above is the last option. The last option clearly describes the illustration of the construction of a perpendicular to a line from a point on the line where you start on a point in the line. Using an arbitrary radius, draw arcs intersecting the line <span> at two points. </span>
Hope this answers the question. Have a nice day.