Answer:
C
Step-by-step explanation:
ley y = f(x) and rearrange making x the subject
y =
- 1 ( add 1 to both sides )
y + 1 =
( multiply both sides by (x + 5)
(y + 1)(x + 5) = 1 ← expand factors using FOIL
xy + 5y + x + 5 = 1 , that is
xy + x + 5y + 5 = 1 ( factor first/second and third/fourth terms on left side )
x(y + 1) + 5(y + 1) = 1 ← factor out (y + 1) from each term on left side
(y + 1)(x + 5) = 1 ( divide both sides by (y + 1) )
x + 5 =
( subtract 5 from both sides )
x =
- 5
Change y back into terms of x with x =
(x) , then
(x) =
- 5 where x ≠ - 1
You can google it and it’ll show you how to do so
Answer:
g is decreasing for all x less than or equal to -1
Step-by-step explanation:
The graph of the function y = |x| looks like a "vee."
g(x) = |x + 1| - 7 moves that graph 1 unit to the <u>left</u><em> </em>(I know, it looks backwards!) and down 7 units. See attached image.
Function g(x) is decreasing for all
.
Is it SV squared? Or times 2
<h3>
Answer: E) x^5</h3>

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Explanation:
We simply take half of the exponent 10 to get 5. This applies to square roots only.
So the rule is 
A more general rule is
![\sqrt[n]{a^b} = a^{b/n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Eb%7D%20%3D%20a%5E%7Bb%2Fn%7D)
If n = 2, then we're dealing with square roots like with this problem. In this case, a = x and b = 10.