Question

Autumn is thinking about buying a car. The table below shows the projected value of two different cars for three years.

Answer 1

Part A

Car 1

• 26000 - 32000 = 32000 - 38000 = -6000
• Since the difference is common this is a linear function

Car 2

• 32300/38000 = 27465/32300 = 0.85
• Since the ratio is common this is an exponential function

Part B

Car 1

• V(x) = 38000 - 6000x

Car 2

• V(x) = 38000*0.85ˣ

Part C

Find V(6) for both cars and compare

Car 1

• V(6) = 38000 - 6*6000 = 2000

Car 2

• V(6) = 38000*0.85⁶ = 14331.68

As we see the difference is significant and car 2 has much greater value