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Svet_ta [14]
3 years ago
13

Autumn is thinking about buying a car. The table below shows the projected value of two different cars for three years.

Mathematics
1 answer:
Greeley [361]3 years ago
4 0
<h3>Part A</h3>

<u>Car 1</u>

  • 26000 - 32000 = 32000 - 38000 = -6000
  • Since the difference is common this is a linear function

<u>Car 2</u>

  • 32300/38000 = 27465/32300 = 0.85
  • Since the ratio is common this is an exponential function
<h3>Part B</h3>

<u>Car 1</u>

  • V(x) = 38000 - 6000x

<u>Car 2</u>

  • V(x) = 38000*0.85ˣ
<h3>Part C</h3>

Find V(6) for both cars and compare

<u>Car 1</u>

  • V(6) = 38000 - 6*6000 = 2000

<u>Car 2</u>

  • V(6) = 38000*0.85⁶ = 14331.68

As we see the difference is significant and car 2 has much greater value

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