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Svet_ta [14]
3 years ago
13

Autumn is thinking about buying a car. The table below shows the projected value of two different cars for three years.

Mathematics
1 answer:
Greeley [361]3 years ago
4 0
<h3>Part A</h3>

<u>Car 1</u>

  • 26000 - 32000 = 32000 - 38000 = -6000
  • Since the difference is common this is a linear function

<u>Car 2</u>

  • 32300/38000 = 27465/32300 = 0.85
  • Since the ratio is common this is an exponential function
<h3>Part B</h3>

<u>Car 1</u>

  • V(x) = 38000 - 6000x

<u>Car 2</u>

  • V(x) = 38000*0.85ˣ
<h3>Part C</h3>

Find V(6) for both cars and compare

<u>Car 1</u>

  • V(6) = 38000 - 6*6000 = 2000

<u>Car 2</u>

  • V(6) = 38000*0.85⁶ = 14331.68

As we see the difference is significant and car 2 has much greater value

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The mean of the values in a data set is c. If each of the values in the data set were multiplied by 6, what would be the mean of
oksian1 [2.3K]

Answer:

Mean of the data would be 6c

Step-by-step explanation:

<u>Rule to Remember:</u> Whenever each term of the data is multiplied by the same number, the new mean is previous mean multiplied by that number.

In this case, original value of mean was c. Each value of the data is multiplied with 6 so a result the new mean would be 6 times the original mean i.e. 6c

Let us consider that original values in the data set are x, y and z. Their mean would be:

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If each value of the data is multiplied with 6, the new values would be 6x, 6y and 6z. The mean in this case will be:

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We can see from above that the new mean is 6 multiplied to the original mean.

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7 0
3 years ago
Question 2:
Mashutka [201]
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