Let S be the sum,
S = 2 + 4 + 6 + ... + 2 (n - 2) + 2 (n - 1) + 2n
Reverse the order of terms:
S = 2n + 2 (n - 1) + 2 (n - 2) + ... + 6 + 4 + 2
Add up terms in the same positions, so that twice the sum is
2S = (2n + 2) + (2n + 2) + (2n + 2) + ... + (2n + 2)
or
2S = n (2n + 2)
Divide both sides by 2 to solve for S :
S = n (n + 1)
Answer: 7
Step-by-step explanation:
Step 1: Since it is asking how much each hat costed. We would divide.
42$ divide 6 = 7$ per hat
Answer:
18.84
Step-by-step explanation:
3.14 · 6
18.84
4.1.....the 4 in the ones place is 10 times bigger then the 4 in the tenths place and 100 times bigger then the 4 in the hundredths place and 1000 times bigger then the 4 in the thousandths place
2.4..the 4 in the tenths place is 10 timed bigger then the 4 in the hundredths place and 100 times bigger then the 4 in the thousandths place
3.14...the 4 in the hundredths place is 10 times bigger then the 4 in the thousandths place
5.124...this 4 in the thousandths place is the smallest
Answer:
<u>24</u>
Step-by-step explanation:
w - 9 = 15
+9 +9
w= 24
Hope this helped you- have a good day bro cya)
