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Julli [10]
3 years ago
14

54) Ashley and Nicole each improved their yards by planting daylilies and ornamental grass. They

Mathematics
1 answer:
Assoli18 [71]3 years ago
3 0

Answer:

Daylilies- $11, Ornamental grass- $7

Step-by-step explanation:

For this one, you want to convert this into simultaneous equations.

If we let d be cost of one daylily and o be cost of one bunch of ornamental grass, we can write the equations as 2d+3o=43 and 6d+3o=87.

From there, we can see they share a like term (3o), so we subtract one equation from the other (since they both are preceded by a +). This gives 4d=44.

Dividing both sides by 4 isolates d, leaving d=$11.

We can substitute this value into either equation to work out o (I'm using the first one as it is easier). This makes it 2×11+3o=43, or 22+3o=43.

From there, we subtract 22 from both sides, giving 3o=21, and dividing by 3 gives a final result of o=$7.

**This content involves writing and solving simultaneous equations, which you may wish to revise. I'm always happy to help!

All working out:

<em>d- cost of one daylily o- cost of one bunch of ornamental grass</em>

<em>2d+3o=43 6d+3o=87</em>

<em />

6d+3o=87

 -     -     -

2d+3o=43

=     =    =

4d      =44

÷4        ÷4

d        =11

2d+3o=43

2×11+3o=43

22+3o=43

3o=21

o=7

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Answer:

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Step-by-step explanation:

The length to width ratios of the rectangles are ...

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4 years ago
Kathi and Robert Hawn had a pottery stand at the annual Skippack Craft Fair. They sold some of their pottery at the original pri
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Answer:

The number sold at $12.50 is  25

The number sold at $9.50 is 62

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations:

x 12.50 + y 9.50=901.50

x+y= 87

Where

x= number of pottery pieces sold

y= number of pottery pieces sold at a decreased price  

Multiplying the second equation by 9.50, and subtracting the second equation to the first equation:

12.50 x + 9.50y = 901.50

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9.50 x+ 9.50 y= 826.5

__________________

3 x = 75

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x =75/3

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How many palindromes of length 5 can you form using letters with the following properties: they start with a consonant, and the
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There are 21 consonants that can serve as the first and last letters. There are 5 vowels that can serve as the 2nd and 4th letters. There are 20 remaining consonants that can serve as the 3rd letter. (The same consonant cannot appear in all three places.)

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