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musickatia [10]
3 years ago
13

It is computed that when a basketball player shoots a free throw the odds in favor of his making our 23 to 3 find the probabilit

y that when does basketball player shoot a free throw he misses it out of every 100 free throws he attempts on the average how many should he make

Mathematics
1 answer:
denis-greek [22]3 years ago
4 0

Answer:

Step-by-step explanation:

So think like a percent 3 percent of 23 of mean multiply so first 23 divided by 100 equals what then to check the answer multiply it by 3

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43 grams of copper and 7grams other metals in a birdhouse, 83 grams of copper and 17 grams of other metals. Which one has more c
andrew-mc [135]

Answer: cage  I

Step-by-step explanation:

Given

43 gm of copper and 7 gram of other metal

Another cage has 83 gram of copper and 17 gm of other metals

Here, the percentage of copper is

For the first case

\Rightarrow \dfrac{43}{43+7}\times 100=86\%

For the second case

\Rightarrow \dfrac{83}{83+17}\times 100=83\%

So, the cage-I has more percentage of copper

6 0
3 years ago
Evaluate. 5 5/8 plus 1 7/8
Alika [10]

Answer:

should be 7 and 4, 8ths

Step-by-step explanation:

......

4 0
3 years ago
Please help! <br> (Multiple choice)
Anni [7]

Answer:

a if it in that order, b if it in the other order and c and d does not make sense

Step-by-step explanation:

3 0
3 years ago
Help pls (fill in the blank)
Bogdan [553]
Answer:
2
14
56

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7 0
3 years ago
A company in Maryland has developed a device that can be attached to car engines, which it believes will increase the miles per
HACTEHA [7]

Answer:

About 0.72

Step-by-step explanation:

Given the data:

With device : 22.6, 23.4, 28.4, 29, 29.3, 20.0

Without device :26.9, 24.4, 20.8, 20.8, 20.2, 26.0, 28.1, 25.6

Using calculator:

With device data:

Sample size (n1) = 6

Degree of freedom (df1) = 6 - 1 = 5

Mean(m1) = 25.45

Variance (s²1) = 15.631

Without device data:

Sample size (n2) = 8

Degree of freedom (df2) = n - 1 = 7

Mean (m2) = 24.1

Variance (s²2) = 9.54

s²t = ((df1/(df1 + df2)) * s²1) + ((df2/(df1 + df2)) * s²2)

s²t = ((5/(5+7)*15.63) + ((7/(5+7))*9.54)

= ((5/12) * 15.63) + ((7/12) * 9.54) = 12.0775

s²m1 = s²t/n1 = 12.0775/6 = 2.0123

s²m2 = s²t/n2 = 12.0775/8 = 1.511

T - statistic :

Tstat = (m1 - m2)/√(s²m1 + s²m2)

Tstat = (25.45 - 24.10) / √(2.0123 + 1.511)

Tstat= 1.350/√3.5233

Tstat = 1.350 / 1.8770455

Tstat = 0.7192153 = 0.72

8 0
3 years ago
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