How many milliliters of 0.100 m naoh are needed to completely neutralize 25.0 ml of 0.250 m h3po4 ?
1 answer:
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<u>Answer:</u> The percentage yield of water is 9.5 %
<u>Explanation:</u>
We are given:
Moles of hydrogen = 14 moles
Moles of oxygen = 10 moles
The chemical equation for the formation of water from hydrogen and oxygen follows:
By Stoichiometry of the reaction:
2 moles of hydrogen gas reacts with 1 mole of oxygen gas
So, 14 moles of hydrogen gas will react with = of oxygen gas
As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent
Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of hydrogen gas produces 2 moles of water
So, 14 moles of hydrogen gas will produce = of water
To calculate the percentage yield of water, we use the equation:
Experimental yield of water = 1.33 moles
Theoretical yield of water = 14 moles
Putting values in above equation, we get:
Hence, the percent yield of the water is 9.5 %.