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Artist 52 [7]
3 years ago
15

In which of the following elevator situations would the acceleration be positive. Select TWO answers

Physics
1 answer:
kap26 [50]3 years ago
4 0

Both options 5 and 6

Explanation:

Let us consider option 5,

In option 5 body is moving up with initial velocity lower than that of final velocity which gets accelerated. Therefore the acceleration is positive in this case.

Let us consider option 6,

In option 6 body is moving down with initial velocity lower than that of final velocity which gets accelerated. Therefore the acceleration is positive in this case.

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A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate. What is
Aleksandr [31]

Answer:

The acceleration of the crate is 1.8 m/s² so the answer is a.

Explanation:

The very first thing you must do when solving this problem is to draw a free body diagram. (The body diagram is attached to this answer)

So once we got the free body diagram, we can analyze it and build our sum of forces in the x and y directions. Notice that according to the diagram, there are 4 forces to this problem, Normal (N), Weight (W), kinetic friction (fk) and the 750N force.

As one may see in the free body diagram, two of the forces are vertical forces: N and W, so we can use them to build a sum of forces:

Starting with the sum of forces in the y-direction, we get:

ΣF_{y}=0

We set the sum equal to zero because there is no movement in the y-direction, so the system is in vertical equilibrium.

so the sum will be:

N-W=0

when solving for N we get that:

N=W

where W is found by multiplying the mass of the crate by the acceleration of gravity:

N=250kg*9.8m/s²

N=2450N

Once we found the normal force, we can use it to find the kinetic friction which is given by the following formula:

f_{k}=Nμ

where μ is the kinetic friction coefficient.

So we get that the kinetic friction is:

f_{k}=2450N*0.12

so

f_{k}=294

With this information we can go ahead and find the sum of horizontal forces:

ΣF_{x}=ma

In this case the sum is equal to mass times acceleration because the crate is moving horizontally due to the action of a force, so it will have an acceleration.

so the sum of forces look like this:

750N-f_{k}=ma

so

750N-294N=(250kg)a

when solving for a we get:

a=\frac{759N-294N}{250kg}\\ \\a=1.8m/s^{2}

so the crate's acceleration is 1.82m/s².

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3 years ago
Two charges are separated by a distance 'd' and exert a mutual attractive force of 'f' on each other. if the distance is decreas
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Peanut butter an jelly crackers are the best
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In order to increase the amount of work completed it is necessary to
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Do all you can in one big day that you have time off or work on one thing then work on the other at the same time

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3 years ago
Read 2 more answers
If you swim with the current in a river, your speed is increased by the speed of the water; if you swim against the current, you
Blababa [14]

Answer:

11.23%

Explanation:

Lets take

Speed of man in still water =u= 1.73 m/s

Speed of flow of water = v=0.52 m/s

When swims in downward direction then speed of man = u + v

When swims in upward direction then speed of man = u - v

Lets time taken by man when he swims in downward direction is t_1 and when he swims in downward direction is t_2

Lets distance is d and it will be remain constant in both the case

d=(u+v)t_1

d=(u-v)t_2

(1.73+0.52)t_1=(1.73-0.52)t_2

t_2=1.85t_1

Time taken in still water

2 d= t x 1.73

t=1.15 x d sec

t_1=0.44d\ sec

t_2=0.82d\ sec

total time in current = 0.82 +0.44 d=1.26 d sec

So the percentage time

percentage\ time =\dfrac{1.28-1.15}{1.15}

 Percentage time =11.32%

So it will take 11.32% more time as compare to still current.

5 0
3 years ago
A rock is dropped from a vertical cliff. The rock takes 6.00 s to reach the ground below the cliff. What is the height of the cl
Lana71 [14]

Answer:

180 m

Explanation:

The rock follows a free-fall motion - so the vertical distance covered can be found by using the equation

h=\frac{1}{2}gt^2

where

g = 10 m/s^2 is the acceleration due to gravity

t = 6.00 s is the time of the fall

Substituting these data, we find the height of the cliff:

h=\frac{1}{2}(10 m/s^2)(6.00 s)^2=180 m

4 0
4 years ago
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