Explanation:
PRIMERO ENCUENTRAS EL PESO DEL PARACAIDISTA
= 65 kg(
) = 637 N
CON LA FÓRMULA DE LA ENERGÍA POTENCIAL
U = 637 N(6000 m - 3500 m) = 1592500 J
How many nanoseconds does it take light to travel 3.50 ft in vacuum?
1 answer:
Answer:3.56 nanosecond
In this case, you are asked the time and given the light distance(3.5ft)
To answer this question you would need to know the velocity of light. Speed of light is <span>299792458m/s. Then the calculation would be:
time= distance/speed
time= 3.5 ft / (</span>299792458m/s) x 0.3048 meter/ 1 ft= 3.56
second or 3.56 nanosecond
In this case, you are asked the time and given the light distance(3.5ft)
To answer this question you would need to know the velocity of light. Speed of light is <span>299792458m/s. Then the calculation would be:
time= distance/speed
time= 3.5 ft / (</span>299792458m/s) x 0.3048 meter/ 1 ft= 3.56
You might be interested in